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lakkis [162]
3 years ago
5

Convert 65,000,000 to scientific notation. (3 points)

Mathematics
1 answer:
yarga [219]3 years ago
8 0

Answer:

6.5x10^7

Step-by-step explanation:

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Polly decides to cut the extra-large pizza into 12 equal slices, how much of the pizza is 2 slices in decimal form?
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Answer: 0.5

Step-by-step explanation:

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3 years ago
Please answer this question now
shusha [124]

Hi there! :)

Answer:

\huge\boxed{V = 359.01 mm^{3} }

Use the formula V = 1/3(bh) to solve for the volume of the cone where b = πr² where π ≈ 3.14:

Find the area of the base:

b = π(7)²

b = 49π

b = 153.86 mm²

Find the volume:

V = 1/3(153.86 · 7)

V = 1/3(1077.02)

V = 359.006 ≈ 359.01 mm³.

4 0
3 years ago
A zoologist is studying four very closely related feline species. She wishes to compare their gestation periods. An observationa
diamong [38]

Answer:

p_v= 0.01

Since the significance level is 0.05 we see that pv so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different, NOT to conclude that the all the means are different.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

Solution to the problem

The hypothesis for this case are:

Null hypothesis: \mu_{A}=\mu_{B}=\mu_{C}= \mu_D

Alternative hypothesis: Not all the means are equal \mu_{i}\neq \mu_{j}, i,j=A,B,C,D

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have p=4 groups and on each group from j=1,\dots,p we have n_j individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2  

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2  

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2  

And we have this property  

SST=SS_{between}+SS_{within}  

And in order to test this hypothesis we need to ue an F statistic and for this case the p value calculated is

p_v= 0.01

Since the significance level is 0.05 we see that pv so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different NOT to conclude that the all the means are different.

8 0
3 years ago
a model of a car is amde to a scale of 1:40. the volume of the model is 45cm^3. calcualte the volume of the car. give your answe
spin [16.1K]

The volume of the car is 1800cm^3 which is equivalent to 0.0018m^3

<h3>Scale modelling</h3>

Given the scale factor that model of a car is amde to a scale of 1:40, Giving that the model as 45cm^3, this means that;

1 = 45cm^2

Determine the volume of the car

40 = x

Find the ratio

1/40 = 45/x

x = 40*45

x = 1800cm^3

x = 0.0018m^3

Hence the volume of the car is 1800cm^3 which is equivalent to 0.0018m^3

Learn more on scale factor here; brainly.com/question/25722260

#SPJ1

6 0
2 years ago
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