The amount of seawater that will be displaced would be 1.3274 x
<h3>Density and volume</h3>
Density = mass/volume.
Since a floating object displaces its own weight, a 4247 tons ship will also displace the same amount of water.
4247 tons of seawater = 3.8528 x g
volume of 3.8528 x g seawater = mass/density = 3.8528 x g/1.025 = 3758829268.29 cubic centimeter.
3758829268.29 = 132741.80 or 1.3274 x
More on density can be found here: brainly.com/question/15164682
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<span>Answer: 6.1 g of Ca(NO₃)₂•4H₂O and 5.5 g of KIO₃
</span>
<span>Explanation:
</span>
1) Calculate the number of moles of <span>Ca(NO₃)₂ in 10.0 g
</span>
i) molar mass of <span>Ca(NO₃)₂ = 40.1 g/mol + 2x126.9 g/mol + 2x3x16.0 g/mol = 389.9 g/mol
</span>
<span>ii) Formula: number of moles = mass in grams / molar mass
</span>number of moles = 10.0 g / 389.9 g/mol = 0.02565 moles of Ca(NO₃)₂
<span>
</span><span>2) Write the chemical equation to state the mole ratio:</span>
<span />
<span>i) Ca(NO₃)2•4H₂O(s) + 2KIO₃(s) --> Ca(IO₃)₂(s) + 2KNO₃ + 4H₂O
</span>
ii) mole ratio: 1 mol Ca(NO₃)2•4H₂O(s) : 2 mol KIO₃(s) : 1 mol <span>Ca(IO₃)₂(s)
</span>
3) Use proportionality to find the actual number of moles
<span>
</span><span>i) </span>Ca(NO₃)₂•4H₂O(s)
1 mol <span>Ca(NO₃)₂•4H₂O(s) / 1 mol Ca(IO₃)₂ = x / 0.02565 mol Ca(IO₃)₂ => x = 0.02565 mol </span>Ca(NO₃)₂•4H₂O(s)
molar mass of <span><span>Ca(NO₃)₂•4H₂O(s)</span> = 40.0g/mol + 2x14.0g/mol + 2x3x16.0g/mol + 4x18.0g/mol = 236.0g/mol
</span>
<span>mass in grams = number of moles x molar mass = 0.02565 mol x 236.0 g/mol = 6.1 g
</span>ii) KIO₃
<span />
<span>1mol KIO₃/1molCa(IO₃)₂ = x / 0.02565 mol Ca(IO₃)₂ => x = 0.02565 mol KIO₃</span>
<span>molar mas of KIO₃ = 39.1 g/mol + 126.9 g/mol + 3x16.0 g/mol = 214.0 g/mol
</span>
mass in grams = 0.02565 mol x 214.0 g/mol = 5.5 g
Answer:
9.368g/mL
Explanation:
The density is defined as the mass of a compound in a determined volume.
Based on Archimedes' law, the volume of the piece of metal is the difference between the volume of the water + the inmersed piece - the original volume of water. That is:
<em>Volume of the metal:</em>
257.5mL - 229.0mL = 28.5mL
As the mass of the metal is 267.0g; its density is:
<em>Density:</em>
267.0g / 28.5mL =
<h3>9.368g/mL</h3>
Answer: 7.07 grams
Explanation:
To calculate the moles :
According to stoichiometry :
1 mole of require 1 mole of
Thus 0.052 moles of will require= of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
As 1 mole of give = 1 mole of
Thus 0.052 moles of give = of
Mass of
Thus 7.07 g of will be produced from the given masses of both reactants.