All categories

4 years ago

When moored to a dock, what should you do before casting off while you warm up the engine?

1 answer:

4 0

The correct answer is <span>make sure everyone on board is wearing a life jacket. This is done as a safety precaution in case things go bad because there should always be enough lifej ackets for all people aboard. They can remove them later. The procedure is similar to how flights have you wear the seatbelt in the beginning and the end.</span>

You might be interested in

What is the velocity if your going 105 miles every 10 minutes

Afina-wow [57]

The speed is 10.5 miles per minute, or 630 miles per hour.
We don't know the velocity, because you didn't tell us anything about the direction I'm going.

8 0

3 years ago

Read 2 more answers

A large semi-truck is moving a house from one lot to another. The amount of force required to move the house 15.A horizontally a

dlinn [17]

Answer:

252J

Explanation:

Given parameters:

Distance = 72m

Force = 3.5N

Unknown:

Work done on the house = ?

Solution:

Work done is the force applied to move a body through a particular distance.

Work done = Force x distance

Now insert the parameters and solve;

Work done = 3.5 x 72 = 252J

5 0

3 years ago

When you lift a box off the ground gravity opposes your lifting force.

ivolga24 [154]

Answer:

TRUE?

Explanation:

Im not really sure what your question is.

6 0

3 years ago

What are large glowing balls of plasma held together by their own gravity called?

GarryVolchara [31]

Large glowing balls of plasma held together by their own gravity are called stars

4 0

4 years ago

A steady device in each cycle converts 155 J of work to thermal energy that is released into a reservoir at 340 K. Part A Calcul

sukhopar [10]

Answer:

change in entropy is 3.3034 × $10^{22}$

Explanation:

give data

thermal energy Q = 155 J

temperature T = 340 K

to find out

change in entropy

solution

we know change in entropy formula that is

change in entropy = Q / ( K×T ) ..............1

here K is boltzmann constant that is 1.38 × $10^{-23}$ kg-m²/s²

put these value in equation 1 we get

change in entropy = Q / ( K × T )

change in entropy = 155 / ( 1.38 × $10^{-23}$ × 340 )

change in entropy = 3.3034 × $10^{22}$

so change in entropy is 3.3034 × $10^{22}$

7 0

3 years ago