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3 years ago

N 4. Which of the following can cause a short circuit?

Physics

1 answer:

user100 [1]3 years ago

7 0

Answer:

pretty sure its A

Explanation:

please give brainliest if i'm correct

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Which term names the part of a sound wave by which frequency or pitch is measured?

Oksanka [162]

Answer:

Hertz

Explanation:

How long is a sound wave? Sound frequency (pitch) is measured in Hertz. 1 Hz is one cycle per second.

7 0

2 years ago

how much heat is produced in one hour by an electric iron which draws 2.5ampere when connected to a 100V supply

love history [14]

Explanation:

I=2.5 Ampere ; V=100V ;t = 1 hour=60secs

We know Heat = VIt

H=100×2.5×60=15,000J

6 0

3 years ago

What happens to a cell in an hypotonic solution?

Vesnalui [34]

Answer:

★ In a hypotonic solution, the solute concentration is lower than inside the cell. If the water continues to move into the cell, it can stretch the cell membrane to the point the cell bursts (lyses) and dies.

Explanation:

Hope you have a great day :)

7 0

3 years ago

A relatively small impact crater 20 kilometers in diameter could be made by a comet 2 kilometers in diameter traveling at 25 km/

nadya68 [22]

Answer:

$KE=1.3\times 10^{21}\ J$

$KE=3.1\times 10^{5}\ E$

Explanation:

(a)

Given:

mass of comet, $m=4.2\times 10^{12}\ kg$

velocity of the comet, $v=2.5\times 10^4\ m.s^{-1}$

<u>Now, the kinetic energy of the comet can be given by:</u>

$KE=\frac{1}{2} m.v^2$

$KE=0.5\times 4.2\times 10^{12}\times (2.5\times 10^4)^2$

$KE=1.3\times 10^{21}\ J$

(b)

Given:

energy released by 1 megaton of TNT, $E=4.2\times 10^{15}\ J$

<u>Now the kinetic energy of the comet in terms of energy of 1 megaton TNT:</u>

$KE=\frac{1.3\times 10^{21}}{4.2\times 10^{15}} E$

i.e.

$KE=3.1\times 10^{5}\ E$

4 0

3 years ago

5. A helicopter scoops a load of water out of a lake, to dump on a forest fire. The helicopter exerts 6480

Strike441 [17]

Answer:

h = 250 m

Explanation:

Given that,

The helicopter exerts 6480 N of force on the water while rising high enough to fly over a mountain.

The helicopter does $1.62\times 10^6\ J$ of work on the water lifting it.

We need to find how high does it lift the water. Work done is given by :

$W=Fh\\\\h=\dfrac{W}{F}\\\\h=\dfrac{1.62\times 10^6}{6480}\\\\h=250\ m$

So, it can lift the water to a height of 250 m.

6 0

3 years ago