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3 years ago

Calculate the osmotic pressure of a solution containing 24.6g of glycerin in 250ml of solution at 298K

1 answer:

6 0

The formula to calculate osmotic pressure is
Osmotic Pressure = M R T
M = Molarity
R = Ideal Gas Constant
T = Temperature in Kelvin

So,
24.6/.2254kg=109.139g /kg >>>>> Molarity
109.139 x mols/92 g = 1.186 mols kg^-1
1.186 x 0.08134 x 298 K = 28.755 atm
<span>1.06852 x 0.08134 x 298K= 26.5 atm

The answer is 26.5</span>

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How many total atoms are in 3.3 moles of potassium sulfide, K2S?

marissa [1.9K]

The answer is 363.99 g

3 0

2 years ago

What is the composition, in atom percent, of an alloy that consists of a) 5.5 wt% Pb and b) 94.5 wt% of Sn? Assume that the atom

Anastaziya [24]

Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

Explanation :

First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.

As, 207.2 g of lead contains $6.022\times 10^{23}$ atoms

So, 5.5 g of lead contains $\frac{5.5}{207.2}\times 6.022\times 10^{23}=1.59\times 10^{22}$ atoms

and,

As, 118.71 g of lead contains $6.022\times 10^{23}$ atoms

So, 94.5 g of lead contains $\frac{94.5}{118.71}\times 6.022\times 10^{23}=4.79\times 10^{23}$ atoms

Now we have to calculate the percent composition of Pb and Sn in atom.

$\% \text{Composition of Pb}=\frac{\text{Atoms of Pb}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100$

$\% \text{Composition of Pb}=\frac{1.59\times 10^{22}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=3.21\%$

and,

$\% \text{Composition of Sn}=\frac{\text{Atoms of Sn}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100$

$\% \text{Composition of Sn}=\frac{4.79\times 10^{23}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=96.8\%$

Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Chuge%5Cmathcal%5Cblue%7BQuestion%7D" id="TexFormula1" title="\huge\mathcal\blue{Question}"

nignag [31]

Organic chemistry as the the study of general properties and compositions of organic compounds.

<h3 />

<h3>What is organic chemistry?</h3>

Organic chemistry can be simply defined as the study of organic compounds.

Organic chemistry studies the structure, properties, composition, reactions, and preparation of carbon-containing compounds also known as organic compounds.

Thus, we can defined organic chemistry as the the study of general properties and compositions of organic compounds.

Learn more about organic chemistry here: brainly.com/question/704297

6 0

2 years ago

Read 2 more answers

An element has two naturally occurring isotopes, X-85 with a mass of 84.9118 amu and a natural abundance of 72.17%, and X-87 wit

QveST [7]

Answer:

This element is Rubidium (Rb) and has an average atomic mass of 85.468 u

Explanation:

The average mass of an element is calculated by taking the average of the atomic masses of its stable isotopes.

The enitre atomic mass = 100 % or 1

⇒ this consists of X-85 with 72.17 % abundance with atomic massof 84.9118 g/mol

72.17 % = 0.7217

⇒ this consists of X-87 with 27.83 % abundance with atomic mass of 86.9092 g/mol

27.83 % = 0.2783

To calculate the mass of this isotope we use the following:

0.7271 * 84.9118 + 0.2783 * 86.9092 =85.468 g/mol

This element is Rubidium(Rb) and has an average atomic mass of 85.468 u

5 0

3 years ago

How many atoms of gold are in gold nugget with a mass of 4.25 g

Feliz [49]

Number of Atoms in Gold for given mass can be calculated using following formula,

# of Moles = Number of Atoms / 6.022 × 10²³
Or,
Number of Atoms = Moles × 6.022 × 10²³ ------- (1)

Calculating Moles,
As,
Moles = Mass / M.mass
So,
Moles = 4.25 g / 196.96 g/mol

Moles = 0.0215

Putting value of mole in eq.1,

Number of Atoms = 0.0215 × 6.022 × 10²³

Number of Atoms = 1.299 × 10²²

Result:
4.25 g of Gold Nugget contains 1.299 × 10²² Atoms.

3 0

3 years ago

Read 2 more answers