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irina [24]
3 years ago
15

What is the smallest frequency at which the string can be moved to produce any standing wave?

Physics
2 answers:
aleksklad [387]3 years ago
8 0
The first harmonic would be the smallest frequency for a string to produce a standing wave. In addition, the strings were fixed in a single attachment and have only limited motion. It is because standing waves require a specific medium for the sound to travel in it.
dem82 [27]3 years ago
4 0

Answer:

v/2l the first harmonic of the wave.

Explanation:

Since the first harmonic of standing wave is produced when the wavelength is double of the string length, so that crest and trough of the wave falls over one another to form a standing wave.

As v=fλ and λ=2L (L being the length of the string)

so, f=v/2L

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A solid, uniform sphere of mass 2.0 kg and radius 1.7 m rolls without slipping down an inclined plane of height 5.3 m. what is t
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<span>Answer: Total kinetic energy at the bottom = 0.5(1+0.4) mv^2 = mgh V^2 = 7*9.8/0.7 V = 9.9m/s ω = V/r = 9.9/1.7 = 5.8rad/s Answer c. 5.8 rad/s</span>
7 0
3 years ago
What kind of gas cloud is most likely to give birth to stars? what kind of gas cloud is most likely to give birth to stars? a co
navik [9.2K]
Hello! 

The kind of gas cloud that is most likely to give birth to stars is a cold, dense gas cloud.

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Have a nice day!
7 0
3 years ago
A force of 10 lb is required to hold a spring stretched 4 in. beyond its natural length. How much work W is done in stretching i
Sunny_sXe [5.5K]

Answer:

114.44 J

Explanation:

From Hook's Law,

F = ke................. Equation 1

Where F = Force required to stretch the spring, k = spring constant, e = extension.

make k the subject of the equation

k = F/e.............. Equation 2

Given: F = 10 lb = (10×4.45) N = 44.5 N, e = 4 in = (4×0.254) = 1.016 m.

Substitute into equation 2

k = 44.5/1.016

k = 43.799 N/m

Work done in stretching the 9 in beyond its natural length

W = 1/2ke²................. Equation 3

Given: e = 9 in = (9×0.254) = 2.286 m, k = 43.799 N/m

Substitute into equation 3

W = 1/2×43.799×2.286²

W = 114.44 J

3 0
3 years ago
Read 2 more answers
Question 11 of 11 | Page 11 of 11
KiRa [710]

Answer:

Decreases the time period of revolution

Explanation:

The time period of Cygnus X-1 orbiting a massive star is 5.6 days.

The orbital velocity of a planet is given by the formula,

                                        v = √[GM/(R + h)]

In the case of rotational motion, v = (R +h)ω

                                         ω = √[GM/(R + h)] /(R +h)

Where 'ω' is the angular velocity of the planet

The time period of rotational motion is,

                                     T = 2π/ω

By substitution,

                                      <em>T = 2π(R +h)√[(R + h)/GM] </em>

Hence, from the above equation, if the mass of the star is greater, the gravitational force between them is greater. This would reduce the time period of revolution of the planet.

3 0
3 years ago
while standing on the sidewalk facing the road, you see a bicyclist passing by toward your right. in the reference frame of the
cricket20 [7]

Answer:

Consider frames X and Y:

If X sees Y moving to his right then Y must see X moving to his right.

If this is not true then one can choose one frame over the other ( a favored frame and this is not allowed)

7 0
3 years ago
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