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3 years ago

What is the smallest frequency at which the string can be moved to produce any standing wave?

2 answers:

8 0

The first harmonic would be the smallest frequency for a string to produce a standing wave. In addition, the strings were fixed in a single attachment and have only limited motion. It is because standing waves require a specific medium for the sound to travel in it.

dem82 [27]3 years ago

4 0

Answer:

v/2l the first harmonic of the wave.

Explanation:

Since the first harmonic of standing wave is produced when the wavelength is double of the string length, so that crest and trough of the wave falls over one another to form a standing wave.

As v=fλ and λ=2L (L being the length of the string)

so, f=v/2L

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A block of mass m slides with a speed vo on a frictionless surface and collides with another mass M which is initially at rest.

Rudik [331]

To solve this problem we will apply the concepts related to the conservation of momentum. Momentum can be defined as the product between mass and velocity. We will depart to facilitate the understanding of the demonstration, considering the initial and final momentum separately, but for conservation, they will be later matched. Thus we will obtain the value of the mass. Our values will be defined as

$m_1 = m$

$m_2 = M$

$v_{1i} =v_0$

$v_{2i} = 0$

Initial momentum will be

$P_i = m_iv_{1i}+m_2v_{2i}$

$P_i = mv_0$

After collision

$v_{1f} = v_{2f} = \frac{v_0}{3}$

Final momentum

$P_f = (m_1+m_2)(\frac{v_0}{3})$

$P_f = (m+M)(\frac{v_0}{3})$

From conservation of momentum

$P_f = P_i$

Replacing,

$(m+M)(\frac{v_0}{3})=mv_0$

$(m+M)\frac{1}{3} = m$

$m+M=3m$

$M=3m-m$

$M=2m$

3 0

3 years ago

An object is swung in a horizontal circle on a length of string that is 0.93 m long. Its acceleration is 26.36 m/s2. What is the

Igoryamba

Answer:

The object takes approximately 1.180 seconds to complete one horizontal circle.

Explanation:

From statement we know that the object is experimenting an Uniform Circular Motion, in which acceleration ( $a$ ), measured in meters per square second, is entirely centripetal and is expressed as:

$a = \frac{4\pi^{2}\cdot R}{T^{2}}$ (1)

Where:

$T$ - Period of rotation, measured in seconds.

$R$ - Radius of rotation, measured in meters.

If we know that $a = 26.36\,\frac{m}{s^{2}}$ and $R = 0.93\,m$ , then the time taken by the object to complete one revolution is:

$T^{2} = \frac{4\pi^{2}\cdot R}{a}$

$T = 2\pi\cdot \sqrt{\frac{R}{a} }$

$T = 2\pi\cdot \sqrt{\frac{0.93\,m}{26.36\,\frac{m}{s^{2}} } }$

$T \approx 1.180\,s$

The object takes approximately 1.180 seconds to complete one horizontal circle.

7 0

3 years ago

A cyclist overcomes a resistive force of 30 N in order to cycle 30 m. It takes her 6 seconds to cycle this distance. Calculate t

zmey [24]

Answer:

Power = 15[W]

Explanation:

This problem can be solved using the work definition.

Work is equal to the product of the force by the distance, for this problem we have:

F = force = 30 [N]

d = distance = 30 [m]

w = work = F * d = 30*30 = 900 [J], "units in joules"

The power is defined as the work done in an interval of time.

P = w / t

where:

t = time [s]

therefore

P = w / t

P = 900 / 6

P = 150 [W] "units in watts"

6 0

3 years ago

Particles in which state of matter are the most likely to interact with each other to cause a chemical reaction?

Mazyrski [523]

I think when particles are in the gas form they are most likely to cause a chemical reaction considering the fact that gas particles aren't very controllable and it would make sense that they would react unexpectedly

7 0

3 years ago

A ball on the end of a string is whirled around in a horizontal circle of radius 0.478 m. The plane of the circle is 1.02 m abov

m_a_m_a [10]

Answer:

Explanation:

We shall find first the velocity of ball at the time when string breaks. Let it be v . During its fall on the ground , 1.02 m below, we use the formula

h = 1/2 gt² where t is time of fall .

1.02 = 1/2 x 9.8 x t²

t²= .2081

t = .456

During this time it travels horizontally at distance of 2.5 m with uniform velocity of v

v x .456 = 2.5

v = 5.48 m /s

centripetal acceleration

= v² / r where r is radius of the circular path

= 5.48² / .478

= 62.82 m /s²

3 0

3 years ago