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Elza [17]
3 years ago
10

an object experiences an acceleration of 6.8 meters per second squared. as a result, it accelerates from rest to 24 m per second

. how much distance did it travel during that acceleration?​
Physics
1 answer:
saveliy_v [14]3 years ago
5 0

Answer:

Distance travelled = 84.7m

Explanation:

First, let us find the time taken for the acceleration to go from rest to 24 m/s

Acceleration = \frac{speed}{time} \\time = \frac{speed}{acceleration} \\time = \frac{24}{6.8} \\time = 3.53 s

Next, let us find the distance since we know the speed and the time.

distance = speed × time

distance = 24 × 3.53

distance = 84.72m

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BlackZzzverrR [31]
Hello
Here we must use the equation of motion 
v^2 = u^2 + 2as; where v is final velocity, u is initial velocity, a is the acceleratoin and is the distance travelled.
We select this one because the time of collision is unknown to us.
We know the truck stopped so its final velocity is 0; thus v = 0.
Converting the initial velocity to SI units, we get 3.89 m/s.
The distance traveled, s, is 0.062 meters.
Inserting all of these values into the equation,
0 = (3.89)^2 + 2(a)(0.062)
and solving for a, we get a to be
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The negative sign indicates the acceleration is in the opposite direction to the initial motion, which means the truck decelerated. This is consistent with the given condition.
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4 years ago
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Sliva [168]

Answer:

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