Answer: The students should take 49.67 g acid acetic in benzene solution. With significant digits 4.967X10 g.
Explanation: If 220 g solution 30.2% w/w acetic acid has 66.44 g acid acetic (220 g solution * 30.2%), 49.67 g solution 30.2% acetic acid has 15 g acetic acid (with a simple three rule, 15 g acetic acid*220 g solution/66.44 g acetic acid)
5.6L of O2 means we have 0.25 moles of O2.
As, 1 mole has 6.023*10^23 molecules,
0.25 moles of O2 will have 0.25*6.023*10^23 molecules=1.50575*10^23 molecules
and as 1 molecule of O2 has 2 atoms, so, 1.50575*10^23 molecules will have 2*1.50575*10^23 atoms=3.0115*10^23 atoms of O.
Answer:
Number 1 is A (I'm not sure but i think it is) and Number 2 is correct (I think)
Explanation:
The diatomic molecule H2 has an extremely low boiling point because only weak Vander waals forces are present between the atoms of hydrogen molecule. This weak inter-molecular forces are easily broken when heat is apply resulting in low boiling point.
Answer:
<em>The first three options given out of the five options are correct.</em>
- <em>It collects chemical data.
</em>
- <em>It records real-time sampling data.
</em>
- <em>It processes and stores chemical data.</em>
Explanation:
An electronic air sampler is a device that is used by people to check apprehension of contamination having individuals with the help of certain volume of air sampling.
The Device is used for recording the chemical data of contamination and the real-time data is sampled and recorded and the data is processed and stored. The air sampling is done in two ways.