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Black_prince [1.1K]
3 years ago
13

What is likely happening at the boundary between the Nazca plate and the Pacific plate?

Physics
2 answers:
Nataly_w [17]3 years ago
8 0
<span>The eastern margin is a convergent boundary subduction zone under the South American Plate and the Andes Mountains, forming the Peru–Chile Trench. The southern side is a divergent boundary with the Antarctic Plate, the Chile Rise, where seafloor spreading permits magma to rise.</span>
Alika [10]3 years ago
8 0

Explanation:

The south-eastern side of the Pacific plate is a divergent boundary (the plates are pulled, and not pushed, apart) with the Nazca Plate forming the East Pacific Rise.

The East Pacific Rise is part of the circumglobal system of active volcanic ridges, all of which define the position of diverging plates where new crust is being created. These ridges represent the locus of global shallow-water earthquakes.

I hope you find this information useful and interesting! Good luck!

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an asteroid whose mass is 2.0 x 10^-4 times the mass of earth revolves in a circular orbit around the sun at a distance that is
Xelga [282]

Answer:

0.0002

Explanation:

First you have to solve exponents first, so you solve 10 to the power of negative 4 which is 0.0001 and now you have 2.0x0.0001 and that equals 0.0002

5 0
3 years ago
A child and sled with a combined mass of 48.8 kg slide down a frictionless hill that is 7.05 m high. If the sled starts from res
nexus9112 [7]

Answer:

Speed at bottom of the hill (v) = 11.74 m/s

Explanation:

Given:

Combined mass = 48.8 kg

Height h = 7.05 m

Find:

Speed at bottom of the hill (v)

Computation:

v² = 2gh

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7 0
3 years ago
The wavelength of violet light is about 425 nm (1 nanometer = 1 × 10−9 m). what are the frequency and period of the light waves?
dexar [7]

1) Frequency: 7.06\cdot 10^{14} Hz

The frequency of electromagnetic radiation is given by:

f=\frac{c}{\lambda}

where

c = 3 \cdot 10^8 m/s is the speed of light

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In this case, the wavelength of the radiation is

\lambda=425 nm=425\cdot 10^{-9} m

Therefore the frequency is

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2) Period: 1.42\cdot 10^{-15} s

The period is equal to the reciprocal of the frequency of the wave:

T=\frac{1}{f}

Using the frequency we found previously, f=7.06\cdot 10^{14} Hz, we find:

T=\frac{1}{7.06\cdot 10^{14} Hz}=1.42\cdot 10^{-15} s


5 0
3 years ago
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Answer:What is the half life of the element Lokium?

The half-live of the element Lokium is 4.

Explanation:

sorry if im wrong, have good day

3 0
2 years ago
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