Question

A large lightning bolt consists of a 18.2~\text{kA}18.2 kA current that moved 30.0~\text{C}30.0 C of charge. Assuming a constant current during the discharge, what is the duration of this lightning bolt?

Answer 1

Answer:

The duration of the lightning bolt is 1.65 milliseconds

Explanation:

Current is a physical quantity that tells how much charge (q) pass through a specific surface, and its unit on the International system of units is the ampere (A), that is coulomb over time $\frac{C}{t}$. So current equation is:

$I=\frac{dq}{dt}$

If I is constant then the equation becomes:

$I= \frac{Q}{t}$

With Q the net charge

Solving for t:

$t=\frac{Q}{I}=\frac{30.0C}{18.2\times10^3A}$

$t=1.65\times10^{-3}s=1.65 ms$

Answer 2

Answer:

$1.65\times {-3} \text { s}$

Explanation:

Current is the rate of flow of charge.

$I=\dfrac{Q}{t}$

$t = \dfrac{Q}{I}$

$t = \dfrac{30.0}{18.2\times10^3} =1.65\times {0-3} = 1.65\times {-3} \text { s}$