Answer:
the magnitude and direction of the uniform electric field is 1846.38 N/C and UPWARD respectively
Explanation:
Given the data in the question;
mass m = 1.30 g = 1.30 × 10⁻³ kg
Charge q = +6.90 µC = 6.90 × 10⁻⁶ C
we know that; g = 9.8 m/s
assuming gravity and the electrostatic force are the only forces exerted on the particle, hence the relation is;
F = mg and F = Eq
so
mg = Eq
make E subject of formula
E = mg / q
so we substitute
E = [ (1.30 × 10⁻³) × 9.8 ] / 6.90 × 10⁻⁶
E = 0.01274 / 6.90 × 10⁻⁶
E = 1846.38 N/C
Since the charge is positive ( + ), { direction is Upward }
Therefore, the magnitude and direction of the uniform electric field is 1846.38 N/C and UPWARD respectively
Hooke's Law
F = k. Δx
Δx = 30 cm = 0.3 m
200 = k . 0.3
the spring stretch for 100 N:
Answer:
Explanation:
velocity is the rate of change of displacement with respect to time.
Velocity = displacement/time
If a line runs straight from 0 seconds 5 meters to 10 seconds 30 meters.
The velocity will be expressed as;
v = d2-d2/t2-t1
v = 30-5/10-0
v = 25/10
v = 2.5m/s
Hence her velocity is 2.5m/s
Yes, you need to convert unless the question specifically requires km/h.
Answer:
<em>A</em><em> </em><em>property of matter by which it remains at rest or in motion in the same straight line unless acted upon by some external force</em>