A parallel-plate capacitor made of circular plates of radius 75 cm separated by 0.15 cm is charged to a potential difference of
1000 volts by a battery. Then a sheet of polyvinyldienedifluoride film is pushed between the plates, completely filling the gap between them. How much additional charge flows from the battery to one of the plates when the polyvinyldienedifluoride film is inserted
1 answer:
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Answer:
Capacitance, C = 26.1 picofarad
Explanation:
It is given that,
Side of square, x = 4.3546 cm = 0.043546 m
Distance between electrodes, d = 0.6408 mm = 0.0006408 m
Voltage, V = 73.68 V
Capacitance of parallel plates is given by :
or
C = 26.1 picofarad
So, the capacitance of the capacitor is 26.1 picofarad. Hence, this is the required solution.