Answer:
0.239 T
Explanation:
Applying,
F = Bvqsin∅................ Equation 1
Where F = magnetic force, B = magnetic Field, q = charge of a proton, v = velocity of proton, ∅ = angle between the velocity and the magnetic field.
make B the subject of the equation
B = F/(vqsin∅)................. Equation 2
From the question,
Given: F = 1.15×10⁻¹³ N, v = 3.0×10⁶ m/s, ∅ = 90°(perpendicular)
Constant: q = 1.602 x 10⁻¹⁹ C
Substitute into equation 2
B = 1.15×10⁻¹³ /(3.0×10⁶×1.602 x 10⁻¹⁹×sin90°)
B = 1.15×10⁻¹³/(4.806×10⁻¹³)
B = 0.239 T.
Hence the magnetic field = 0.239 T
<span>The concept of plate tectonics regards the earth's CRUST as broken into a number of TECTONIC PLATES that are in motion relative to each other</span>
