An object is placed at a distance of 60 cm from a concave lens of focal length 30cm.find the position and nature of the image?

Physics

1 answer:

ladessa [460]3 years ago

5 0

Answer:

using the lens formula: 1/f = 1/u + 1/v

focal length f = -30 (negative because it is concave lens)

object distance u = 60

image distance v= unknown

1/-30 = 1/60 + 1/v

v = -20

So, the image is 20cm from lens (on the same side along with the object), and it is virtual (because of negative sign) and erect (concave lens must produce erect images).

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Answer:

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3 years ago

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Misha Larkins [42]

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Explanation:

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