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lina2011 [118]
4 years ago
13

A squirrel jumps into the air with a velocity of 7 m/s at an angle of 20 degrees. What is the maximum height reached by the squi

rrel?
Physics
1 answer:
Marina CMI [18]4 years ago
7 0

Answer:

.3m

Explanation:

Apex

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CNA Secondary and Preparatory School
ale4655 [162]

Answer:

2:13 2) cm' c6462.

Explanation:

3 0
3 years ago
2. A person began running due east and covered 15 kilometers in 2.0 hours. What is the average velocity of the person?
Angelina_Jolie [31]

Answer:

7.5 km/h (2.1 m/s) due east

Explanation:

The average velocity of the person is given by:

v=\frac{d}{t}

where

d is the displacement

t is the time taken

In this problem,

d = 15 km is the displacement

t = 2.0 h is the time elapsed

so the average velocity is

v=\frac{15 km}{2.0 h}=7.5 km/h

and the direction is the same as the displacement (east).

We can also convert the velocity into SI units (m/s). We have:

d = 15 km = 15,000 m

t = 2.0 h * 3600 s/h = 7200 s

v=\frac{15,000 m}{7200 s}=2.1 m/s

4 0
3 years ago
Read 2 more answers
Which is not an element? Water , Arsenic, sodium, Aluminum
MrRa [10]

Answer:

water

Explanation:

water is not an element, it is a molecule

3 0
4 years ago
Read 2 more answers
If two objects A and B have the same kinetic energy but A has three times the momentum of B, what is the ratio of their inertias
Thepotemich [5.8K]

Answer:

\frac{inertia_B}{inertia_A}=9

Explanation:

First of all, let's remind that:

- The kinetic energy of an object is given by K=\frac{1}{2}mv^2, where m is the mass and v is the speed

- The momentum of an object is given by p=mv

- The inertia of an object is proportional to its mass, so we can write I=km, where k just indicates a constant of proportionality

In this problem, we have:

- K_A = K_B (the two objects have same kinetic energy)

- p_A = 3 p_B (A has three times the momentum of B)

Re-writing both equation we have:

\frac{1}{2}m_A v_A^2 = \frac{1}{2}m_B v_B^2\\m_A v_A = 3 m_B v_B

If we divide first equation by second one we get

v_A = 3 v_B

And if we substitute it into the first equation we get

m_A (3 v_B)^2 = m_B v_B^2\\9 m_A v_B^2 = m_B v_B^2\\m_B = 9 m_A

So, B has 9 times more mass than A, and so B has 9 times more inertia than A, and their ratio is:

\frac{I_B}{I_A}=\frac{km_B}{km_A}=\frac{9m_A}{m_A}=9

7 0
3 years ago
Let two objects of equal mass m collide. Object 1 has initial velocityv, directed to the right, and object 2 isinitially station
3241004551 [841]
<span>Our equation 1 would be
m*v=M*V1+m*V2
v=V1+V2
 v-V1=V2 

the equation 2 would look like this
 </span>V^2=V1^2+V2^2  
V^2-V1^2=V2^2
(V-V1)*(V+V1)=V2^2Dividing with the 1
V+V1=V2 
8 0
3 years ago
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