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Maslowich
3 years ago
5

Consider the following information.

Chemistry
1 answer:
brilliants [131]3 years ago
3 0

Answer:

The molecular formula for A is C2H4(NO3)2

The molecular formula for B is C2H6O2

Explanation:

I linked an image that will show the work.

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the us and the soviet union

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The Hawaiian islands are a unique chain of islands because they are not
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Read 2 more answers
Question 13 (1 point)
crimeas [40]
Its a compound because they come together
7 0
3 years ago
If 50 ml of 0.235 M NaCl solution is diluted to 200.0 ml what is the concentration of the diluted solution
Helen [10]

This is a straightforward dilution calculation that can be done using the equation

M_1V_1=M_2V_2

where <em>M</em>₁ and <em>M</em>₂ are the initial and final (or undiluted and diluted) molar concentrations of the solution, respectively, and <em>V</em>₁ and <em>V</em>₂ are the initial and final (or undiluted and diluted) volumes of the solution, respectively.

Here, we have the initial concentration (<em>M</em>₁) and the initial (<em>V</em>₁) and final (<em>V</em>₂) volumes, and we want to find the final concentration (<em>M</em>₂), or the concentration of the solution after dilution. So, we can rearrange our equation to solve for <em>M</em>₂:

M_2=\frac{M_1V_1}{V_2}.

Substituting in our values, we get

\[M_2=\frac{\left ( 50 \text{ mL} \right )\left ( 0.235 \text{ M} \right )}{\left ( 200.0 \text{ mL} \right )}= 0.05875 \text{ M}\].

So the concentration of the diluted solution is 0.05875 M. You can round that value if necessary according to the appropriate number of sig figs. Note that we don't have to convert our volumes from mL to L since their conversion factors would cancel out anyway; what's important is the ratio of the volumes, which would be the same whether they're presented in milliliters or liters.

5 0
3 years ago
Please help me outttt
leonid [27]

Answer:

4.) 9, 1, and 4    5.) 4, 1, and 4

Explanation:

I am not quite sure about this because I cannot remember if the coefficient (the number before the elements) is applied to every element in the compound. If it is then your number of atoms are as follows: CORRECTION: you do not have to apply the coefficient to every element only the one that is after it. So when you back and fix the error your number of atoms will be as follows:

number 4

H: 9

P: 1

O: 4

number 5:

H: 4

S: 1

O: 4

you can calculate the number of atoms present in this compound by multiplying the coefficient and the subscripts of each atom.

hope this helped you :)

7 0
3 years ago
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