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3 years ago

A charged atom is called a(n) _____. proton electrolyte isotope ion

Physics

2 answers:

lakkis [162]3 years ago

5 0

Answer:

A charged atom is called ion.

Explanation:

Proton : Protons are positively charged particle.

Electrolyte : A chemical compound that dissociates into ions. it is called electrolyte. they have ability of transport electric charge.

Isotopes : Isotopes have same number of proton but different number of neutrons in atom.

Ion : A charged atom is called ion. When an atom loses the electron then the atom is positive ion. When the atom gains the electron then the atom is negative ion.

Hence, A charged atom is called ion.

Basile [38]3 years ago

3 0

A charged Atom is actually called an ion, this charge occurs due to the indifference of electrons that are found outside the main nucleus of the atom.

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A 1.6 Kg bird that is flying through the air has 220 J of kinetic energy. How fast is the bird flying?

xxTIMURxx [149]

Answer:

v = 16.58 m/s

Explanation:

Given that,

Mass of a bird, m = 1.6 kg

Kinetic energy of the bird, K = 220 J

We need to find the speed of the bird. The formula for the kinetic energy is given by :

$E=\dfrac{1}{2}mv^2$

Where

v is the speed of the bird

So,

$v=\sqrt{\dfrac{2E}{m}}$

Put all the values,

$v=\sqrt{\dfrac{2\times 220}{1.6}}\\\\v=16.58\ m/s$

So, the speed of the bird is equal to 16.58 m/s.

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3 years ago

Which is an example of a passive solar energy system?

dem82 [27]

Answer:

b) sunlight shining through windows warms a massive interior wall

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3 years ago

A Carnot engine takes 3000 J from a reservoir at 600 K, does some work, and discards some heat to a reservoir at 300 K. What is

exis [7]

Answer: 50%

Explanation: efficiency=power input/power output ×100

Eff.=300/600 ×100

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4 years ago

An automobile tire is inflated with air originally at 10.0°C and normal atmospheric pressure. During the process, the air is com

solong [7]

Answer:

(a) $3.81\times 10^5\ Pa$

(b) $4.19\times 1065\ Pa$

Explanation:

<u>Given:</u>

$T_1$ = The first temperature of air inside the tire = $10^\circ C =(273+10)\ K =283\ K$

$T_2$ = The second temperature of air inside the tire = $46^\circ C =(273+46)\ K= 319\ K$

$T_3$ = The third temperature of air inside the tire = $85^\circ C =(273+85)\ K=358 \ K$

$V_1$ = The first volume of air inside the tire

$V_2$ = The second volume of air inside the tire = $30\% V_1 = 0.3V_1$

$V_3$ = The third volume of air inside the tire = $2\%V_2+V_2= 102\%V_2=1.02V_2$

$P_1$ = The first pressure of air inside the tire = $1.01325\times 10^5\ Pa$

<u>Assume:</u>

$P_2$ = The second pressure of air inside the tire

$P_3$ = The third pressure of air inside the tire
n = number of moles of air

Since the amount pof air inside the tire remains the same, this means the number of moles of air in the tire will remain constant.

Using ideal gas equation, we have

$PV = nRT\\\Rightarrow \dfrac{PV}{T}=nR = constant\,\,\,(\because n,\ R\ are\ constants)$

Part (a):

Using the above equation for this part of compression in the air, we have

$\therefore \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\\\Rightarrow P_2 = \dfrac{V_1}{V_2}\times \dfrac{T_2}{T_1}\times P_1\\\Rightarrow P_2 = \dfrac{V_1}{0.3V_1}\times \dfrac{319}{283}\times 1.01325\times 10^5\\\Rightarrow P_2 =3.81\times 10^5\ Pa$

Hence, the pressure in the tire after the compression is $3.81\times 10^5\ Pa$ .

Part (b):

Again using the equation for this part for the air, we have

$\therefore \dfrac{P_2V_2}{T_2}=\dfrac{P_3V_3}{T_3}\\\Rightarrow P_3 = \dfrac{V_2}{V_3}\times \dfrac{T_3}{T_2}\times P_2\\\Rightarrow P_3 = \dfrac{V_2}{1.02V_2}\times \dfrac{358}{319}\times 3.81\times 10^5\\\Rightarrow P_3 =4.19\times 10^5\ Pa$

Hence, the pressure in the tire after the car i driven at high speed is $4.19\times 10^5\ Pa$ .

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A rocket is fired from rest from the ground (y = 0) at time t0 = 0 s. As the rocket is burning its fuel, it moves vertically upw

elixir [45]

Answer:

Explanation:

attached is the solution

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