Answer:
a) The proeutectoid phase is known like cementite and its chemical formula is Fe₃C
b) The kilograms of total ferrite and is 0.8311 kg
The kilograms of total cementite is 0.1689 kg
c) The kilograms of total cementite is 0.9343 kg
Explanation:
Given:
1 kg of austenite
1.15 wt% C
Cooled to below 727°C
Questions:
a) What is the proeutectoid phase?
b) How many kilograms each of total ferrite and cementite form, Wf = ?, Wc = ?
c) How many kilograms each of pearlite and the proeutectoid phase form, Wp = ?
d) Schematically sketch and label the resulting microstructure
a) The proeutectoid phase is known like cementite and its chemical formula is Fe₃C
b) To get the mass of the total ferrite form:
![W_{f} =\frac{C_{cementite}-C_{2} }{C_{cementite}-C_{1} }](https://tex.z-dn.net/?f=W_%7Bf%7D%20%3D%5Cfrac%7BC_%7Bcementite%7D-C_%7B2%7D%20%20%7D%7BC_%7Bcementite%7D-C_%7B1%7D%20%20%7D)
Here,
Ccementite = composition of cementite = 6.7 wt%
C₁ = composition of phase 1 = 0.022 wt%
C₂ = composition of alloy = 1.15 wt%
Substituting values:
![W_{f} =\frac{6.7-1.15}{6.7-0.022} =0.8311kg](https://tex.z-dn.net/?f=W_%7Bf%7D%20%3D%5Cfrac%7B6.7-1.15%7D%7B6.7-0.022%7D%20%3D0.8311kg)
To get the mass of the total cementite:
![W_{c} =\frac{C_{2}-C_{1}}{C_{cementite}-C_{1} } =\frac{1.15-0.022}{6.7-0.022} =0.1689kg](https://tex.z-dn.net/?f=W_%7Bc%7D%20%3D%5Cfrac%7BC_%7B2%7D-C_%7B1%7D%7D%7BC_%7Bcementite%7D-C_%7B1%7D%20%7D%20%3D%5Cfrac%7B1.15-0.022%7D%7B6.7-0.022%7D%20%3D0.1689kg)
c) The mass of pearlite:
![W_{p} =\frac{6.7-1.15}{5.94} =0.9343kg](https://tex.z-dn.net/?f=W_%7Bp%7D%20%3D%5Cfrac%7B6.7-1.15%7D%7B5.94%7D%20%3D0.9343kg)
d) In the diagram you can see the different compositions (pearlite, proeutectoid cementite, ferrite, eutectoid cementite)