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Fofino [41]
3 years ago
13

A refrigerator operates on average for 10.0 hours an day. If the power rating is the refrigerator is 709 w how much electrical e

nergy does the fridge use in one day
Engineering
1 answer:
Varvara68 [4.7K]3 years ago
6 0

Answer:

61257.6 kW per day

Explanation:

The rating of the refrigerator is given as : 709 w

This means the power consumption is 709 joules per second

The operating time is given as 10 hours.

Change hours to second as

1 hour = 3600 seconds

10 hours = 36000 seconds

Apply the rating as;

709 w = 1 s

?         = 36000 seconds

perform cross product to get;

709 * 36000= 25524000 w

25524000 = 25524kW

For a day, 24 hours will be;

25524 kW = 10 hours

?                 =24 hours

={24*25524}/10 = 61257.6 kW per day

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Given the vector current density J = 10rho2zarho − 4rho cos2 φ aφ mA/m2:
Xelga [282]

Answer:

(a) Current density at P is J(P)=180.\textbf{a}_{\rho}-9.\textbf{a}_{\phi} \ (mA/m^2)\\.

(b) Total current I is 3.257 A

Explanation:

Because question includes symbols and formulas it can be misunderstood. In the question current density is given as below;

J=10\rho^2z.\textbf{a}_{\rho}-4\rho(\cos\phi)^2\textbf{a}_{\phi}\\

where \textbf{a}_{\rho} and \textbf{a}_{\phi} unit vectors.

(a) In order to find the current density at a specific point <em>(P)</em>, we can simply replace the coordinates in the current density equation.  Therefore

J(P(\rho=3, \phi=30^o,z=2))=10.3^2.2.\textbf{a}_{\rho}-4.3.(\cos(30^o)^2).\textbf{a}_{\phi}\\\\J(P)=180.\textbf{a}_{\rho}-9.\textbf{a}_{\phi} \ (mA/m^2)\\

(b) Total current flowing outward can be calculated by using the relation,

I=\int {\textbf{J} \, \textbf{ds}

where integral is calculated through the circular band given in the question. We can write the integral as below,

I=\int\{(10\rho^2z.\textbf{a}_{\rho}-4\rho(\cos\phi)^2\textbf{a}_{\phi}).(\rho.d\phi.dz.\textbf{a}_{\rho}})\}\\\\I=\int\{(10\rho^2z).(\rho.d\phi.dz)\}\\\\\\

due to unit vector multiplication. Then,

I=10\int\(\rho^3z.dz.d\phi

where \rho=3,\ 0. Therefore

I=10.3^3\int_2^{2.8}\(zdz.\int_0^{2\pi}d\phi\\I=270(\frac{2.8^2}{2}-\frac{2^2}{2} )(2\pi-0)=3257.2\ mA\\I=3.257\ A

4 0
4 years ago
why are you directed not to touch the holder or discharge tube whule the power to the supply to the gas tube is on?
dedylja [7]

Every profession has its rules and regulations. The reason why we are directed not to touch the holder or discharge tube while the power to the supply to the gas tube is on because;

  • The discharge tube can create about 5000 V of voltage when connected to power.

  • The gas discharge tubes is often very hot when used with the power supplies and one should not to touch them until they are cooled down.

We  have been taught to stay far was from a high voltage area or system and also we should not dare to touch it.

There are different reasons why we should about these high voltage system or are; The reason is that;

  • Because high voltages often reduce the impedance of our skin, thereby making electricity to flow through our bodies.

Learn more about Voltage from

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5 0
2 years ago
Explain and show work:
belka [17]

Answer:

  5

Explanation:

The sum of the digits of the number is ...

  (4+1+3)+(4+6+5)+(7+8+9) = 8+15+24 = 47

The sum of those digits is 4+7=11, and those digits sum to 1+1 = 2.

That is, the value of the number mod 9 (or 3) is 2.

The ones digit is odd, so the value of the number mod 2 is 1.

This combination of modulo values tells you the mod 6 result is 5.

_____

<em>Additional comment</em>

We can look at the (mod2, mod3) values of the numbers 0 to 5:

  0 ⇒ (0, 0)

  1 ⇒ (1, 1)

  2 ⇒ (0, 2)

  3 ⇒ (1, 0)

  4 ⇒ (0, 1)

  5 ⇒ (1, 2) . . . . the mod {2, 3} results we have for the number of interest.

This process of adding up the digits repeatedly is referred to as "casting out 9s." The result of it is the modulo 9 value of the number (with 0 mapped to 9). Checking the mod 9 result of arithmetic operations is one quick way to spot certain kinds of errors. It can also be used as part of a divisibility test for 3 or 9.

3 0
3 years ago
Technician A says the compressor is the dividing line of the refrigeration system, low- to high-side. Technician B says the expa
Fiesta28 [93]

The statements regarding the refrigeration system as expressed by the technicians are correct. Hence, the correct statement is Option c.

<h3>What is a refrigeration system?</h3>

Refrigeration systems are a crucial process in the industry and home applications as they carry out cooling or keep the room temperature at a preferred value.

The missing information in the question is:

A.technician A only

B.technician B only

C.both A and B

D.neither A or B

Hence, The statements regarding the refrigeration system as expressed by the technicians are correct.  the correct statement is Option c.

Learn more about Refrigeration systems:

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7 0
2 years ago
In the idealized Otto cycle, heat is added during: a. Isentropic Compression b. Constant (minimum) volume c. Constant (maximum)
docker41 [41]

Answer:

(b) Constant (minimum) volume

Explanation:

In the idealized Otto cycle there are 4 process that are

  • Reversible adiabatic compression  
  • Addition of heat at constant volume
  • Reversible adiabatic expansion
  • Rejection of constant volume

So from above discussion we can see that heat is added when there is constant (minimum) volume which is given in option (b) so option (b) will be the correct answer

3 0
3 years ago
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