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Marysya12 [62]
3 years ago
14

Boat A and Boat B have the same mass. Boat A's velocity is three times greater than that of Boat B. Compared to

Physics
2 answers:
Zarrin [17]3 years ago
7 0

Answer:

nine times as much.

Explanation:

K.E of A = 9 times K.E of B

Nikitich [7]3 years ago
3 0

Answer:

D) nine times as much

Explanation:

its correct

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Chegg ) Alice owns 20 grams of a radioactive isotope that has a half-life of ln(4) years. (a) Find an equation for the mass m(t)
stepladder [879]

Answer:

m(t)=20e^{-0.5t}

Explanation:

Given:

Initial mass of isotope (m₀) = 20 g

Half life of the isotope (t_{1/2}) = (ln 4) years

The general form for the radioactive decay of a radioactive isotope is given as:

m(t)=m_0e^{-kt}

Where,

m(t)\to mass\ after\ 't'\ years\\t\to years\ passed\\k\to rate\ of\ decay\ per\ year

So, the equation is: m(t)=20e^{-kt}

At half-life, the mass is reduced to half of the initial value.

So, at t=t_{1/2},m(t)=\frac{m_0}{2}. Plug in these values and solve for 'k'. This gives,

\frac{m_0}{2}=m_0e^{-k\times\ln 4}\\\\0.5=e^{-k\times\ln 4}\\\\Taking\ natural\ log\ on\ both\ sides,we\ get:\\\\\ln(0.5)=-k\times \ln 4\\\\k=\frac{\ln 0.5}{-\ln 4}=0.5

Hence, the equation for the mass remaining is given as:

m(t)=20e^{-0.5t}

8 0
4 years ago
What is the resultant of the vectors shown?
ad-work [718]

Answer:

Option B

Explanation:

Option A is the wrong answer because the horizontal vector is in the opposite direction.

Option C is the wrong answer as the horizontal vector is in the opposite direction and all the vectors are connected head to tail [of the arrows] [Triangle law of vector addition]

Option D is the wrong answer as the horizontal vector is in the opposite direction.

5 0
2 years ago
A 0.40-kg mass, attached to the end of a 0.75-m string, is whirled around in a circular horizontal path. If the maximum tension
hichkok12 [17]

To solve this problem we will apply the concepts given from the circular movement of the bodies for which we have that the centripetal Force is defined as a product between the mass and the velocity squared at the rate of rotation, mathematically this is

F_c = \frac{mv^2}{r}

Where,

m = Mass

v = Velocity

r = Radius

Our values are given as

m = 0.4kg\\r = 0.75m\\F_c = 450N

Rearranging to find the velocity we have that,

F_c = \frac{mv^2}{r}

v = \sqrt{\frac{F_c * r}{m}}

v = \sqrt{\frac{450 * 0.75}{0.4}}

v = 29.0474m/s

Therefore the  maximum speed can the mass have if the string is not to break is 29m/s

3 0
3 years ago
Is it True or false a muscle strain occurs when a ligament is torn away from the bone
Anit [1.1K]
I think the answer its false i dont know how to explain that but it is false that what my teacher told me 
6 0
3 years ago
A 1000 kg mass car moved in a straight, horizontal motion, with a speed of 20m / s, when it was involved in an accident. It was
emmasim [6.3K]

Answer:

average value of the resulting force

Explanation:

The average module value of this resulting force is equivalent to 2.0. 10⁵ N.

The impulse of a force can be calculated by the product of the intensity of the force applied by the time interval in which it is applied -

I = F.Δt

Where,

F = Strength in Newtons

Δt = time interval in seconds

I = Impulse in N.s

The impulse of a force is equivalent to the variation of the amount of movement it causes in the body.

I = ΔQ

The amount of movement is a vector quantity that results from the multiplication of the mass of a body by its speed. Its direction and direction are the same as the velocity vector of the body.  

Q = m-V

As the car goes to rest after the application of force, the amount of final movement of the car is equivalent to zero.

I = 0 - mV

F. Δt = - mV

F. 0,1 = - 1000. 20

F = - 20000/0,1

F = 200,000 N

F = 2,0. 10⁵ N

6 0
3 years ago
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