Answer:

Explanation:
Given:
Initial mass of isotope (m₀) = 20 g
Half life of the isotope
= (ln 4) years
The general form for the radioactive decay of a radioactive isotope is given as:

Where,

So, the equation is: 
At half-life, the mass is reduced to half of the initial value.
So, at
. Plug in these values and solve for 'k'. This gives,

Hence, the equation for the mass remaining is given as:

Answer:
Option B
Explanation:
Option A is the wrong answer because the horizontal vector is in the opposite direction.
Option C is the wrong answer as the horizontal vector is in the opposite direction and all the vectors are connected head to tail [of the arrows] [Triangle law of vector addition]
Option D is the wrong answer as the horizontal vector is in the opposite direction.
To solve this problem we will apply the concepts given from the circular movement of the bodies for which we have that the centripetal Force is defined as a product between the mass and the velocity squared at the rate of rotation, mathematically this is

Where,
m = Mass
v = Velocity
r = Radius
Our values are given as

Rearranging to find the velocity we have that,




Therefore the maximum speed can the mass have if the string is not to break is 29m/s
I think the answer its false i dont know how to explain that but it is false that what my teacher told me
Answer:
average value of the resulting force
Explanation:
The average module value of this resulting force is equivalent to 2.0. 10⁵ N.
The impulse of a force can be calculated by the product of the intensity of the force applied by the time interval in which it is applied -
I = F.Δt
Where,
F = Strength in Newtons
Δt = time interval in seconds
I = Impulse in N.s
The impulse of a force is equivalent to the variation of the amount of movement it causes in the body.
I = ΔQ
The amount of movement is a vector quantity that results from the multiplication of the mass of a body by its speed. Its direction and direction are the same as the velocity vector of the body.
Q = m-V
As the car goes to rest after the application of force, the amount of final movement of the car is equivalent to zero.
I = 0 - mV
F. Δt = - mV
F. 0,1 = - 1000. 20
F = - 20000/0,1
F = 200,000 N
F = 2,0. 10⁵ N