Is this a question?ummmmm
Answer
given,
mass of railroad = 2060 Kg
mass of sumo wrestler = 241 Kg
speed = 5.3 m/s
a) using conservation of momentum
m v = (m + M) V
241 x 5.3 = (241 + 2060)V
V = 0.556 m/s
b) Let v be the relative speed
Again using conservation of momentum
241 x 5.3 =241 x (5.3+v) + 2060 v
241 x 5.3 =241 x 5.3+241 x v + 2060 v
2301 v = 0
v = 0 m/s
c) the speed of the flatcar if he then turns and run sat 5.3 m/s relative to the flat car opposite his original direction
241 x 5.3 =241 x (v - 5.3) + 2060 v
241 x 5.3 = - 241 x 5.3+241 x v + 2060 v
2301 v = 2554.6
v = 1.11 m/s
It could combine with any other metal on the periodic table. If I had answers to choose from, then maybe I could help you better.
Hope this helps!!!
Answer:
0.446 mm
0.066 V/m
Explanation:
Given
We are given the length of the copper cable L = 3.30 km and the potential difference is V = 220 V
Solution
(a) We want to find the diameter d of the cable when the dissipated power is P = 50W. The power consumed by the cable depends on its resistance R and it is given by equation in the form
P= V^2/R (1)
Where V is the voltage in the cable. Now let us solve equation (1) for R and plug our values for V and P into equation (1) to get R
R = V^2/P = (220)^2/(50) = 968Ω
Now we can determine the diameter of the copper wire. The resistance R of the wires depends on the area of the wire, resistivity and the length of the cable. Where equation gives us the relationship between these variables in the form
R = pL/π*r^2 (solve for r)
r = √pL/πR (2)
Now we can plug our values for Rep and L into equation (2) to get the radius of the cable where p for copper equals 1.72 x 10-8 Ω m
r =√pL/πR
= √1.72 x 10-8 *3300m/968
= 0.234 mm
Therefore, the diameter is d= 2r = 2(0.234 mm) = 0.446 mm
(b) To determine the electric field we can use the values for the potential difference across the cable and the length of the cable, where the electric field is inversely proportional to the length of the cable as next
E =V/L
=220/3300m
= 0.066 V/m
