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elena-s [515]
3 years ago
13

A wave can be best defined as P.S pls help

Physics
1 answer:
Sidana [21]3 years ago
4 0

Answer:

It should be A. Disturbance that travels through a medium or space, transmitting energy from one point to another.

I hope this helped you :)

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Let us be two cylindrical conductors connected in parallel, to which a potential difference of V = 170V is applied. The two cond
PSYCHO15rus [73]

The equivalent resistance of the two cylindrical conductors connected in parallel is 466 ohm.

<h3>Resistance</h3>

Resistance is a measure of the opposition to flow of electric current. It is measured in ohms.

It is given by the formula:

R=\rho\frac{l}{A} \\\\where\ l=length,A=area,\rho=resistivity

Given that R₂ = 469 ohm, hence:

R_2=\rho\frac{l_2}{A_2} \\\\469=\rho\frac{l_2}{\pi r_2^2}

But l₁ = 6l₂, r₁ = (1/5)r₂, hence:

R_1=\rho \frac{l_1}{A_1}=\rho *\frac{6l_2}{[\pi (1/5)r_2]^2} =150 * \rho \frac{l_2}{[\pi r_2]^2}=30*469=70350\ ohm

The equivalent resistance (R) is:

R=\frac{R_1R_2}{R_1+R_1}=\frac{469*70350}{469+70350}  =466\ ohm

The equivalent resistance of the two cylindrical conductors connected in parallel is 466 ohm.

Find out more on resistance at: brainly.com/question/17563681

3 0
2 years ago
What is the worlds most common acid and also the worlds most commin base
mrs_skeptik [129]

Answer: Water is the world's most common acid and base.

3 0
2 years ago
One heater uses 310 W of power when connected by itself to a battery. Another heater uses 180 W of power when connected by itsel
igor_vitrenko [27]

Answer:

55.8W

Explanation:

P= V^2/R

R= V^2/P

For series connection

Req= R1+ R2= V^2/310 + V^2/180

R=V^2/P= V^2/310 + V^2/180

But V^2 will cancel out

P= 1/(1/310 + 1/180)

P= 55.8W

8 0
3 years ago
Read 2 more answers
A rotating fan completes 1200 revolutions every minute. consider the tip of a blade, at a radius of 0.19 m. through what distanc
ser-zykov [4K]

The tip of the fan moves through the outer side of the circle.

So it moves a distance of perimeter of circle in one revolution.

Perimeter of circle = 2\pir, where r is the radius of circle.

In this case radius of circular motion = 0.19 meter

So perimeter of circle = 2\pi*0.19 = 0.38\pi = 1.194 m

So distance does the tip move in one revolution = 1.194 meter

5 0
3 years ago
Water exits straight down from a faucet with a 1.96-cm diameter at a speed of 0.55 m/s. The volume flow rate of the water as it
d1i1m1o1n [39]

Answer:

Q = 165.95 cm³ / s,  1)    v = \sqrt{0.55^2 + 19.6 y},  2)  v = 2.05 m / s,

3)  d₂ = 1.014 cm

Explanation:

This is a fluid mechanics exercise

1) the continuity equation is

         Q = v A

where Q is the flow rate, A is area and v is the velocity

         

the area of ​​a circle is

        A = π r²

radius and diameter are related

        r = d / 2

substituting

       A = π d²/4

       Q = π/4   v d²

let's reduce the magnitudes

       v = 0.55 m / s = 55 cm / s

let's calculate

       Q = π/4   55   1.96²

       Q = 165.95 cm³ / s

If we focus on a water particle and apply the zimematics equations

        v² = v₀² + 2 g y

where the initial velocity is v₀ = 0.55 m / s

        v = \sqrt{0.55^2 + 2  \ 9.8\  y}

        v = \sqrt{0.55^2 + 19.6 y}

2) ask to calculate the velocity for y = 0.2 m

        v = \sqrt{0.55^2 + 19.6 \ 0.2}

        v = 2.05 m / s

3) We write the continuous equation for this point 2

        Q = v₂ A₂

        A₂ = Q / v₂

let us reduce to the same units of the SI system

        Q = 165.95 cm³ s (1 m / 10² cm) ³ = 165.95 10⁻⁶ m³ / s

        A₂ = 165.95 10⁻⁶ / 2.05

        A₂ = 80,759 10⁻⁶ m²

area is

        A₂ = π/4   d₂²

        d₂ = \sqrt{4  A_2 / \pi }

        d₂ = \sqrt{ \frac{4 \ 80.759 \ 10^{-6} }{\pi } }

        d₂ = 10.14 10⁻³ m

        d₂ = 1.014 cm

4 0
3 years ago
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