Answer:
(a). The electric potential at 1.650 cm is 
.
(b). The electric potential at 2.81 cm is 
.
Explanation:
Given that,
Radius of sphere R=2.81 cm
Charge = +2.35 fC
Potential at center of sphere
(a). We need to calculate the potential at a distance r = 1.60 cm
Using formula of potential difference
The electric potential at 1.650 cm is .
(b). We need to calculate the potential at a distance r = R
Using formula of potential difference
The electric potential at 2.81 cm is .
Hence, This is the required solution.
Answer:
acceleration due to gravity = 9.8m/s^2
universal gravitational constant= 6.67×10 ^_11 nm^2 kg_2
now, ratio=9.8/6.67×10^_11.
If the shopping cart is parallel to the ground, the weight is acting vertically downward, then force is equal to weight. The normal force will be acting perpendicular to the ground,and acting upward opposite of the weight.
Answer:
1. Decreases,
2. Increases,
3. Increases
Explanation:
The heat which is a product of sun's energy, is transferred from the sun to the earth through radiation, conduction or convention. This heat passes through the earth atmosphere, then warms it , before becoming heat energy.
Therefore, Heat is transferred from the sun to the earth via electromagnetic waves . Because of this transfer, the entropy of the sun DECREASES, the entropy of the earth INCREASES and the entropy of the sun-earth system INCREASES.
Answer:
Explanation:
Based on the wave model of light, physicists predicted that increasing light amplitude would increase the kinetic energy of emitted photoelectrons, while increasing the frequency would increase measured current.
Contrary to the predictions, experiments showed that increasing the light frequency increased the kinetic energy of the photoelectrons, and increasing the light amplitude increased the current.
Based on these findings, Einstein proposed that light behaved like a stream of particles called photons with an energy of \text{E}=h\nuE=hνstart text, E, end text, equals, h, \nu.
The work function, \PhiΦ\Phi, is the minimum amount of energy required to induce photoemission of electrons from a metal surface, and the value of \PhiΦ\Phi depends on the metal.
The energy of the incident photon must be equal to the sum of the metal's work function and the photoelectron kinetic energy:
