Answer:
1.67g/cm3
Explanation:
The formula for density is 
. The m variable stands for mass and the v variable stands for volume.
The mass of the brown sugar is 10.0g and the volume is 6.0cm3, so we can plug those values into the equation.
Rounded to 3 significant figures, the density of the block of brown sugar is 1.67 g/cm3. If the mass is in grams and the volume is in cm3, the unit for the final answer is (grams per centimetres cubed).
http://century.rochester.k12.mn.us/cms/One.aspx?portalId=3086882&pageId=6133921
Hope this helps!
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Answer:
I. Increasing pressure will allow more frequent successful collision between particles due to the particles being closer together.
II. Rate of reaction increases due to more products being made; as increased pressure favours the exothermic side of the equilibrium.
III. Increasing temperature provides particles lots of (Kinetic) energy, for more frequent successful collision due to the particles moving at a faster rate than before. However, favouring the endothermic side of the equilibrium due to lots of energy required to break and form new bonds.
IV. Rate of reaction increases due to increase temperature favouring both directions of the equilibrium - causing products to form faster.
Hope this helps!
Answer:
B. 13.7 mm
Explanation:
by similarity of rectangular triangles, we have:
(1) Δ ABC and Δ AB'C'
∴ AB/AB' = AC/AC'
∴ hypotenuse (AB)² = AC² + BC².....Pythagorean theorem
⇒ AB² = (51 mm)² + (13 mm)²
⇒ AB² = 2770 mm²
⇒ AB = 52.63 mm
(2) Δ AB'C' :
∴ hypotenuse (AB')² = AC'² + B'C'²
∴ B'C' = 3.5 mm
from (1):
⇒ AB' = (AB)(AC') / AC = (52.63)(AC') / (51 mm)
⇒ AB' = 1.032AC'.......(3)
(3) in (2):
⇒ (1.032AC')² = AC'² + (3.5)²
⇒1.065AC'² = AC'² + 12.25
⇒ 0.065AC'² = 12.25
⇒ AC'² = 188.462
⇒ AC' = √188.462
⇒ AC' = 13.72 mm
There are 10 millimeters in 1 centimeter
