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Alexxx [7]
3 years ago
7

How are the geographical equator, meteorological equator, and ITCZ related? What happens at the ITCZ?

Chemistry
1 answer:
scoray [572]3 years ago
4 0
The ITCZ<span> or </span>Intertropical Convergence Zone<span> is a region on Earth that experiences ... The </span>ITCZ<span> lies near the </span>equator<span>, bringing precipitation caused by convection. ... </span>Related<span>. The Poetry of Sailors: What Are Doldrums and Trade Winds</span>
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Question 2 (1 point)
Alexxandr [17]

Answer:

a mole have have wrong becouse i understand

4 0
3 years ago
Which diagram shows a pair of electrons that have opposite spins?<br> 011<br> 1<br> 011<br> o 11h
Neporo4naja [7]

Answer:

1 one is the right........

5 0
3 years ago
Having studied the data for patterns and trends, you should now be able to draw
avanturin [10]

Answer:

The situation given here is imaginary such that the life of Rock has to be found using the half-life of the element lokium that has been found inside the rock.

Half-life of any material is the amount of time taken by that particular material to decay. Now the amount of lokium found in rock can show after how many half-lives this amount has been left out.

The time elapsed will be log (L) atoms X half-life.

Explanation:

3 0
2 years ago
If a 250mL beaker weighs 13.473g and the same beaker plus 2.2 mL of water weighs 15.346g. How much does the 2.2 mL of water, alo
Sindrei [870]

Given :

A 250 ml beaker weighs 13.473 g .

The same beaker plus 2.2 ml of water weighs 15.346 g.

To Find :

How much does the 2.2 ml of water, alone, weigh .

Solution :

Now, mass of water is given by :

\text{Mass of water alone = Total mass - Mass of beaker alone}\\\\Mass =15.346-13.473\ g\\\\Mass =1.873\ g

Therefore , mass of 2.2 ml of water alone is 1.873 g .

Hence , this is the required solution .

4 0
3 years ago
Carbon (C): 1s(H)2s(I)2p(J)<br> What is H, I, and J equal?
Artemon [7]

Answer:

H =2; I = 2; J = 2  

Explanation:

Carbon is element 6 in the Periodic Table.  

Start at element 1 (H) and count from left to right until you reach element 6 (C).

You get the electron configuration

C: 1s² 2s²2p².

Thus,

H =2; I = 2; J = 2

3 0
3 years ago
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