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grigory [225]
3 years ago
11

At what speed will a car round a 52-m-radius curve, banked at a 45???? angle, if no friction is required between the road and ti

res to prevent the car from slipping? (g = 9.8 m/s2)a. 27 m/s
b. 17 m/s
c. 23 m/s
d. 35 m/s
Physics
1 answer:
Serhud [2]3 years ago
4 0

Answer:

c. 23 m/s

Explanation:

\theta = Angle of banking = 45°

r = Radius of turn = 52 m

g = Acceleration due to gravity = 9.81 m/s²

v = Velocity of car

As the car is tilted we have the relation

tan\theta=\dfrac{v^2}{rg}\\\Rightarrow v=\sqrt{tan\theta rg}\\\Rightarrow v=\sqrt{tan45\times 52\times 9.8}\\\Rightarrow v=22.57432\ m/s\approx 23\ m/s

The velocity of the car is 23 m/s if the car is not slipping

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