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grigory [225]
3 years ago
11

At what speed will a car round a 52-m-radius curve, banked at a 45???? angle, if no friction is required between the road and ti

res to prevent the car from slipping? (g = 9.8 m/s2)a. 27 m/s
b. 17 m/s
c. 23 m/s
d. 35 m/s
Physics
1 answer:
Serhud [2]3 years ago
4 0

Answer:

c. 23 m/s

Explanation:

\theta = Angle of banking = 45°

r = Radius of turn = 52 m

g = Acceleration due to gravity = 9.81 m/s²

v = Velocity of car

As the car is tilted we have the relation

tan\theta=\dfrac{v^2}{rg}\\\Rightarrow v=\sqrt{tan\theta rg}\\\Rightarrow v=\sqrt{tan45\times 52\times 9.8}\\\Rightarrow v=22.57432\ m/s\approx 23\ m/s

The velocity of the car is 23 m/s if the car is not slipping

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What type of galaxy is M82 based on its appearance in the visible-light view?
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<h2>Answer: irregular</h2>

According to Hubble  galaxies are classified into elliptical, spiral and irregular.

 

It should be noted this classification is based only on the visual appearance of the galaxy, and does not take into account other aspects, such as the rate of star formation or the activity of the galactic nucleus.  

The classification is as follows:  

1. Elliptical galaxies: Their main characteristic is that the concentration of stars decreases from the nucleus, which is small and very bright, towards its edges. In addition, they contain a large population of old stars, usually little gas and dust, and some newly formed stars.  

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In this context, galaxy M82 does not match with the first two types of galaxies, because it has not a defined shape.

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4 0
3 years ago
A 20 cm long spring is attached to a wall. The spring stretches to a length of 22 cm when you pull on it with a force of 100 n.
kenny6666 [7]

Answer:

5000 N/m

Explanation:

Hooke's law for the spring is

F = k \Delta x

where here we have

F = 100 N is the force applied to the spring

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Solving the equation for k, we find the spring constant:

k=\frac{F}{\Delta x}=\frac{100 N}{0.02 m}=5000 N/m

8 0
4 years ago
A missile is moving 1350 m/s at a 25.0 angle
murzikaleks [220]
I will answer both versions assuming what you want to know is the distance it travels up from and over the ground. and how long until it reaches space. 540 meters per second up and over. to reach space which is 100km above sea level, it would take about 5400 minutes
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The driving force for fluid flow is the pressure difference, and a pump operates by raising the pressure of a fluid (by converti
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Answer:

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Explanation:

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3 0
4 years ago
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A large ant is standing on the middle of acircus tightrope that is stretched with tension Ts. The rope has mass per unit length
77julia77 [94]

Answer:

Explanation:

The ant , at some point of time will be standing on the crest of moving wave passing under its feet . At that position the downward acceleration of the ant will be equal to its weight . Hence it will feel weightlessness . So at that time

Acceleration = g

Acceleration at the top position = ω²A where ω is angular velocity and A is amplitude of vibration ( transverse ) of crest .

ω =2 π n where n is frequency of transverse vibration of particles. This angular frequency will be equal to angular  frequency of wave travelling on the rope .

frequency  of travelling  wave

n.= \frac{1}{\gamma}\sqrt{\frac{T}{\mu} }

ω =2 π  x \frac{1}{\gamma}\sqrt{\frac{T}{\mu}

ω² = 4π² x T/γ²μ}

For weightlessness

ω² A = g

A= g x γ²μ / 4π² T

7 0
3 years ago
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