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OLga [1]
3 years ago
8

Sodium and water react according to the equation

Chemistry
1 answer:
elena55 [62]3 years ago
7 0

2Na(s) + 2 H2O (liquid) -> 2 NaOH (aq) + H2 (g)


1) 2 reactants are given, so we have to find which of them is an excess reactant and which of them will react completely.

Convert gram of Na and H2O into moles.

M(Na) =23.0 g/mol

10.0 g Na*1 mol Na/23.0 g Na≈0.4349 mol Na


M(H2O) = 2*1.0 +16.0 = 18.0 g/mol

50.0 g H2O*1 mol H2O/18.0 g H2O =2.778 mol H2O


2Na(s) + 2 H2O (liquid) -> 2 NaOH (aq) + H2 (g)

from equation 2 mol 2 mol

given 0.4349 mol 2.778 mol


We can see that H2O is an excess reactant, so we are going to find amount of H2 using Na.


2)

2Na(s) + 2 H2O (liquid) -> 2 NaOH (aq) + H2 (g)

from equation 2 mol 1 mol

given 0.4349 mol x mol


x=(0.4349*1)/2 =0.21745 mol H2


3) mass of H2

0.21745 mol H2 * 2.0 g H2/1 mol ≈ 0.435 g H2


Answer : 0.435 g H2.


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Hope this helps!

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The mass of a solid substance is 21.112 g. If the volume of the solid substance is 19.5 cm3, calculate the density of the substa
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ρ = 1.08 g/cm³

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Volume of the substance (V): 19.5 cm³

Step 2: Calculate the density of the substance

The density (ρ) of a substance is equal to its mass divided by its volume.

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ρ = 21.112 g / 19.5 cm³

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Look at this balanced chemical reaction: N2 + 3H2 2NH3
stepladder [879]

Answer: A mass of 124457.96 g ammonia is produced by reacting a 450 L sample of nitrogen gas at a temperature of 450 K and a pressure of 300 atm.

Explanation:

Given: Volume = 450 L

Temperature = 450 K

Pressure = 300 atm

Using ideal gas equation, moles of nitrogen are calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = tempertaure

Substitute values into the above formula as follows.

PV = nRT\\300 atm \times 450 L = n \times 0.0821 L atm/mol K \times 450 K\\n = \frac{135000}{36.945}\\= 3654.08 mol

According to the given equation, 1 mole of nitrogen forms 2 moles of ammonia. So, moles of ammonia formed by 3654.08 moles of nitrogen is as follows.

2 \times 3654.08 mol\\= 7308.16 mol

As moles is the mass of substance divided by its molar mass. So, mass of ammonia (molar mass = 17.03 g/mol) is as follows.

Moles = \frac{mass}{molar mass}\\7308.16 = \frac{mass}{17.03 g/mol}\\mass = 124457.96 g

Thus, we can conclude that a mass of 124457.96 g ammonia is produced by reacting a 450 L sample of nitrogen gas at a temperature of 450 K and a pressure of 300 atm.

8 0
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