This can be done using integration and vector analysis. By considering a differential element of the line charge distribution dq = Q/a*dy, we could calculate the dFx and dFy and solve for Fx and Fy through integration.
dFx = -xkQdq / (y^2 + x^2)^3/2 = -xkQ^2/a/(y^2+x^2)^(3/2)*dy
Fx = integral from 0 to a -xkQ^2/a/(y^2+x^2)^(3/2)*dy
Fx = -xkQ^2/a*int(0, a, dy/(y^2+x^2)^(3/2))
Fx = -kQ^2/x(a^2+x^2)^(1/2)
dFy = kQy/(y^2+x^2)^(3/2) * dq
dFy = kQ^2/a*y/(y^2+x^2)^(3/2)*dy
Fy = int(0, a, kQ^2/a*y/(y^2+x^2)^(3/2)*dy)
Fy = kQ^2/a int(0, a, dy y/(y^2+x^2)^(3/2))
Fy = kQ^2/a * (1/x - 1/(a^2+x^2)^(1/2))
As we know that
here we know that
now from above equation we have
so image will form on left side of lens at a distance of 15 cm
This image will be magnified and virtual image
Ray diagram is attached below here
Answer:
(b) Torque will increase.
Explanation:
Torque is given as the product of force and moment arm (radius).
τ = F x r
F = τ / r
where;
F is force
τ is torque
r is radius (moment arm)
Keeping force constant, we will have the following;
τ ∝ r
This shows that torque is directly proportional moment arm (radius), thus increase in moment arm, will cause increase in torque.
For instance;
let the constant force = 5 N
let the initial moment arm, r = 2m
Torque, τ = 5 N x 2m = 10 Nm
When the moment arm is increased to 4 m
Torque, τ = 5 N x 4m = 20 Nm
Therefore, at a constant force, increasing in the Moment arm, will cause increase in torque.
Coorect option is "(b) Torque will increase."
The pyrite will be bigger, because its density is much lower.
I <em>do</em> know that the gold's volume will be 2.5906 (With a bunch more numbers after it)
50 divided by 19.3 = 2.5906
