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Alekssandra [29.7K]

3 years ago

11

A current of 9 A flows through an electric device with a resistance of 43 Ω. What must be the applied voltage in this particular

circuit?
A. 4.8 V
B. 4.8 A
C. 387 V
D. 387 A

1 answer:

blondinia [14]3 years ago

6 0

The answer is D. Hope this helps you!

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Mr smith is designing a race where velocity will be measured.which course would allow velocity to accurately get a winner?

Usimov [2.4K]

Answer:

yes it is allowed to win

Explanation:

a velocity used to measure to take a distance travelled my any thing

5 0

3 years ago

. Suppose that the displacement of an object is related to time according to the expression: x(t) = B t3 . Using dimensional ana

-Dominant- [34]

Answer:

The dimensionality of B is <em>length</em> per cubic <em>time</em>.

Explanation:

Units for displacement and time are <em>length</em> $[L]$ and <em>time</em> $[T]$ , respectively. Then, formula can be tested for dimensional analysis as follows:

$[L] = B\cdot [T]^{3}$

Now, let is clear $B$ to determine its units:

$B = \frac{[L]}{[T]^{3}}$

The dimensionality of B is <em>length</em> per cubic <em>time</em>.

6 0

3 years ago

Light of wavelength 608.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 88.5 cm from the slit.

Effectus [21]

Answer:

The width of the slit is 0.167 mm

Explanation:

Wavelength of light, $\lambda=608\ nm=608\times 10^{-9}\ m$

Distance from screen to slit, D = 88.5 cm = 0.885 m

The distance on the screen between the fifth order minimum and the central maximum is 1.61 cm, y = 1.61 cm = 0.0161 m

We need to find the width of the slit. The formula for the distance on the screen between the fifth order minimum and the central maximum is :

$y=\dfrac{mD\lambda}{a}$

where

a = width of the slit

$a=\dfrac{mD\lambda}{y}$

$a=\dfrac{5\times 0.885\ m\times 608\times 10^{-9}\ m}{0.0161\ m}$

a = 0.000167 m

$a=1.67\times 10^{-4}\ m$

a = 0.167 mm

So, the width of the slit is 0.167 mm. Hence, this is the required solution.

7 0

3 years ago

Lynn rubs a balloon with a piece of wool, which causes the balloon to pick up some of the electric charges from the wool. Lynn t

Hitman42 [59]

Answer:

electrostatics

gravitational forces

Explanation:

rubbing the ballon leads to it acquiring charges that are opposite to that in the wall.the electostatic forces attract the ballon to the wall and tyhe gravitational pull later acts on the ballon causing it to fall down

5 0

3 years ago

Read 2 more answers

Derivation 1.2 showed how to calculate the work of reversible, isothermal expansion of a perfect gas. Suppose that the expansion

stellarik [79]

Answer:

(a) The work done by the gas on the surroundings is, 17537.016 J

(b) The entropy change of the gas is, 73.0709 J/K

(c) The entropy change of the gas is equal to zero.

Explanation:

(a) The expression used for work done in reversible isothermal expansion will be,

where,

w = work done = ?

n = number of moles of gas = 4 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas = 240 K

= initial volume of gas =

= final volume of gas =

Now put all the given values in the above formula, we get:

The work done by the gas on the surroundings is, 17537.016 J

(b) Now we have to calculate the entropy change of the gas.

As per first law of thermodynamic,

where,

= internal energy

q = heat

w = work done

As we know that, the term internal energy is the depend on the temperature and the process is isothermal that means at constant temperature.

So, at constant temperature the internal energy is equal to zero.

Thus, w = q = 17537.016 J

Formula used for entropy change:

The entropy change of the gas is, 73.0709 J/K

(c) Now we have to calculate the entropy change of the gas when the expansion is reversible and adiabatic instead of isothermal.

As we know that, in adiabatic process there is no heat exchange between the system and surroundings. That means, q = constant = 0

So, from this we conclude that the entropy change of the gas must also be equal to zero.

Explanation:

6 0

3 years ago