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IrinaK [193]
3 years ago
9

Joe walked 1200m East and then turned and walked 600m West. Which statement is true about Joe’s walk

Physics
2 answers:
Slav-nsk [51]3 years ago
8 0

Answer:

Velocity is 1m/s

Explanation:

Vera_Pavlovna [14]3 years ago
7 0

Answer:

which statement is true about his walk? he walked 1200m then went back 600m

Explanation:

because he walked 1200m east the 600m west so it adds up to 600

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Explain what makes up a circuit .
ANEK [815]

Explanation:

An electrical circuit needs:

a source of electrical power (this could be a power plant or a battery)

a material along which the electricity can flow (this may be a copper wire)

something to power (this could be a bulb)

The circuit is connected in a loop. Then, the source of power pushes electrons around the wire. It lights the bulb and continues in the circuit until it is broken.

A simple circuit lights one bulb. More difficult circuits might have several switches and loops. This would allow different groups of lights to be turned on or off at the same time.

( I hope this was helpful) >;D

Read more: All in a Circuit - What Makes a Circuit?, Battery Power, How a Battery Works, Flat!, Home Circuits, Conductors and Insulators - JRank Articles https://science.jrank.org/kids/pages/232/All-in-Circuit.html#ixzz6qWd5gxGf

5 0
3 years ago
Two 10-cm-diameter charged rings face each other, 25 cm apart. The left ring is charged to ? 25 nC and the right ring is charged
MArishka [77]

Answer:

A)   E = 0N/C

B)   0i + 0^^j

C)   F = 0N

D)   0^i  + 0^j

Explanation:

You assume that the rings are in the zy plane but in different positions.

Furthermore, you can consider that the origin of coordinates is at the midway between the rings.

A) In order to calculate the magnitude of the electric field at the middle of the rings, you take into account that the electric field produced by each ring at the origin is opposite to each other and parallel to the x axis.

You use the following formula for the electric field produced by a charge ring at a perpendicular distance of r:

E=k\frac{rQ}{(r+R^2)^{3/2}}               (1)

k: Coulomb's constant = 8.98*10^9Nm^2/C

Q: charge of the ring

r: perpendicular distance to the center of the ring

R: radius of the ring

You use the equation (1) to calculate the net electric field at the midpoint between the rings:

E=k\frac{rQ}{(r^2+R^2)^{3/2}}-k\frac{rQ}{(r^2+R^2)^{3/2}}=0\frac{N}{C}

The electric field produced by each ring has the same magnitude but opposite direction, then, the net electric field is zero.

B) The direction of the electric field is 0^i + 0^j

C) The magnitude of the force on a proton at the midpoint between the rings is:

F=qE=q(0N/C)=0N

D) The direction of the force is 0^i + 0^j

6 0
3 years ago
The activation energy for the isomerization reaction of CH3NC in Problem 14 is 161 kJ mol 1, and the reaction rate constant at 6
astraxan [27]

Answer:

Explanation:

Below is an attachment containing the solution to the question.

5 0
3 years ago
A ball of mass 0.15 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of 0.960 m. b)
Art [367]

Answer:

Explanation:

If v be the velocity just after the rebound

Kinetic energy will be converted into potential energy

1/2 m v² = mgh

v² = 2gh

v = √ 2gh

= √ 2 x 9.8 x .96

= 4.33 m / s

4 0
3 years ago
An object is moving diagonally (down and to the left). You want it to stop moving. In what direction (or
vekshin1
A. Up and to the right
B. Put it in the opposite direction so it won’t go left
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3 years ago
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