What is the potential energy of a spring that is compressed 0.65 m by 25kg block if the spring constant 95 Nm
1 answer:
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Answer:
Explanation:
Let's begin by explaining that according to Kepler’s Third Law of Planetary motion “The square of the orbital period of a planet is proportional to the cube of the semi-major axis
of its orbit”:
(1)
Now, if is measured in years (Earth years), and
is measured in astronomical units (equivalent to the distance between the Sun and the Earth:
), equation (1) becomes:
(2)
So, knowing and isolating
from (2) we have:
(3)
(4)
Finally:
T
his is the distance between the dwarf planet and the Sun in astronomical units
Converting this to kilometers, we have:
Answer:
4.6 years
Explanation:
This is solved using Kepler's third law which says:
Where
T = Orbital period of the planet (in seconds)
a = Distance from the star (in meters)
G = Gravitational constant
M = Mass of the parent star (in kg)
From the information given
We put this into Kepler's law and get:
This when converted to years is 4.6 years.
Answer:
The acceleration of the object is
Explanation:
Given:
Initial velocity of object = 200 feet/second
Final velocity of object = 50 feet/second
Time of travel = 5 seconds
To calculate acceleration of the object we will find the rate of change of velocity with respect to time.
So, acceleration is given by:
where represents final velocity,
represents initial velocity and
is time of travel.
Plugging in values to evaluate acceleration.
The acceleration of the object is (Answer). The negative sign shows the object is slowing down.