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posledela
2 years ago
13

1000 kg car takes travels on a circular track having radius 100 m with speed 10 m/s. What is the magnitude of the centripetal fo

rce acting on the car? *
A- 1 N
B- 100 N
C- 1000 N
D- 10000 N
Physics
1 answer:
Kryger [21]2 years ago
8 0

Answer:

its a

Explanation:

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The LR5 is the specialist submarine for underwater rescue. The average density of seawater is 1028 kg/ m3.
sladkih [1.3K]

Answer:

P = 7196 [kPa]

Explanation:

We can solve this problem using the expression that defines the pressure depending on the height of water column.

P = dens*g*h

where:

dens = 1028 [kg/m^3]

g = 10 [m/s^2]

h = 700 [m]

Therefore:

P = 1028*10*700

P = 7196000 [Pa]

P = 7196 [kPa]

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3 years ago
Which planet moves the fastest and which planet moves slowest? a, b, c, d, e, or f. Explain
Alisiya [41]
D is the point where the planet moves the fastest. This is because it is in the perihelion, where the planet is moving at it’s fastest pace
6 0
1 year ago
Assignments
sladkih [1.3K]

Hello there!

I hope you and your family are staying safe and healthy during this unprecendented time.

A) What is the work done?

Answer: We need to use the formula

w=-F_f(d)

w=-(35)(20)

w=-700J

B) What is the work done on the cart by the gravitational force?  

Alright, we know that the gravitional force is perpendicular to the diplacement. Therefore, we gonna use the following formula:

w=Fdcos90

w=0

C) What is the work done on the cart by the shopper?

This is the easier part, since we already know that the work done by the shopper is the same as the work done by the friction force

W shopper + W friction = 0\\W shopper = W-friction \\W shopper = 700J

D) Find the force the shopper exerts, using energy considerations.

F_f+Fcos25=0\\-35+Fcos25=0\\F=38.6N

E) What is the total work done?

You just need to add them:

w=wshopper+wfriction\\w=0

4 0
3 years ago
How many calories you need per day to maintain your current weight.
Harman [31]
Answer: adult males generally require 2,000-3000 calories per day, and adult females need 1,600-2,400.

3 0
2 years ago
Two lasers are shining on a double slit, with slit separationd.Laser 1 has a wavelength of d/20, whereas laser 2 has a wavelengt
Sophie [7]

Answer:

a) laser 1 has the maximum closest to the central maximum

b) y₂ –y₁ = L 1.66 10⁻²

Explanation:

a), B1, B2)  The expression that describes the constructive interference for a double slit is

            d sin θ = m λ

The pattern is observed on a screen

            tan θ = y / L

Since the angles are very small

           tan θ = sin θ / cos θ = sin θ = y/L

 

           d y / L = m λ  

In this case the laser has a wavelength

           λ ₁ = d/20

We substitute

            d y / L = m d / 20

            m = 1

            y₁ = L / 20

For the laser 2 λ ₂= d / 15

             y₂ = L / 15

When examining the two expressions, laser 1 has the maximum closest to the central maximum

b) the difference between the two patterns is

            y₂- y₁ = L (1/15 - 1/20)

           y₂ –y₁ = L 1.66 10⁻²

C) laser 1 second maximum

          y₁ ’= 2 L / 20

          y₁ ’= L 0.1

Laser 2 third minimum

To have a minimum, the equation must be satisfied

           d sin θ = (m + ½) λ  

           d y / L = (m + ½) λ  

           d y / L = (m + ½) d / 15

           y = L (m +1/2) / 15

           m = 3

           y₂’= L (3 + ½) / 15

           y₂’= L 0.2333

The difference is

           y₁ ’- y₂’ = L (0.1 - 0.2333)

          y₁ ’–y₂’ = L (-0.133)

3 0
3 years ago
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