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Gwar [14]
1 year ago
9

solubility of cu(oh)2 is 2.42 x 10-3 mol/l. calculate ksp and in which direction the reaction is spontaneous if δgº

Chemistry
1 answer:
Simora [160]1 year ago
7 0

Ksp of copper(II) hydroxide Cu(OH)2 is 4.9 x 10-8.

Chemical reaction (dissociation) of copper(II) hydroxide in water:

Cu(OH)2(s) → Cu²⁺(aq) + 2OH⁻(aq).

Ksp(Cu(OH)2) = [Cu²⁺]·[OH⁻]².

[Cu²⁺] = 2.42 x 10-3 mol/l; solubility od copper ions

[OH⁻] = 2[Cu²⁺] = 2 x 2.42 x 10-3 mol/l

[OH⁻] = 4.48 x 10-3 mol/l; solubility of hydroxide ions

Ksp = 2.42 x 10-3 mol/l x (4.48 x 10-3 mol/l)²

Ksp = 4.9 x 10-8

Ksp is the solubility product constant for a solid substance dissolving in an aqueous solution.

Solubility of the compound depends on the temperature of the solution and the structure of that compound.

More info about: brainly.com/question/23946616

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Why is it harder to remove an electron from fluorine than from carbon?
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The overall reaction in a commercial heat pack can be represented as How much heat is released when 4.40 moles of iron are react
vodomira [7]

Answer:

Explanation:

The overall equation for this reaction can be represented as:4 Fe(s) + 3 O_{2(g) }  \to 2Fe_2O_{3(s)} \ \ \ \      \Delta H = -1652  \ kJ

The first question says:

How much heat is released when 4.40 moles of iron is reacted with excess O₂?

Suppose 1652 kJ of heat is being emitted into the surroundings when four(4) moles of Fe reacted with O₂, therefore;

4.40 moles of Fe reacts with:

=\dfrac{4.40 \ moles \times  1652 \ kJ}{4 \ moles}

= 1817.2 kJ of heat will be produced.

The second question says:

How much heat is released when 1.00 mole of Fe_2O_3 is produced?

Given that 1652 kJ of heat is being emitted into the surroundings when two(2) moles of Fe_2O_3 is produced, therefore;

1.00 moles of Fe_2O_3 reacts with:

=\dfrac{1.00 \ moles \times  1652 \ kJ}{2 \ moles}

= 826 kJ of heat will be produced.

To the third question; we have:

How much heat is released when 1.60 g iron is reacted with excess O₂?

We need to find the number of moles of iron first.

We know that number of moles = mass/molar mass

Thus, the molar mass of iron = 55.8 g/mol

number of moles of iron = (1.60g) / (55.8 g/mol)

number of moles of iron = 0.02867 mol

Thus; \dfrac{0.02867\  mol \times  1652 \ kJ }{4 \ mol}

= 11.84 kJ of heat is released.

The last question says:

How much heat is released when 11.8 g Fe and 1.20 g O₂ are reacted?

Again;

the number of moles of Fe = (11.8g) / (55.8 g/mol) = 0.2114 mole of Fe

Thus; \dfrac{0.2114\  mol \times  1652 \ kJ }{4 \ mol}

= 87.31 kJ of heat is released.

On the other hand,

the number of moles of O₂ = (1.20g) / (32 g/mol) = 0.0375 mol of O₂

Thus; \dfrac{0.0375\  mol \times  1652 \ kJ }{3 \ mol}

= 20.65 kJ of heat is released

Therefore, when these two(2) reactants reacted with each other, it is just the smaller amount of heat that would be released because oxygen tends to be the limiting reactant.

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