Ask question

Ask question

All categories

4 years ago

14

A force exerted on an object produces acceleration. If the mass remains the same and the acceleration is doubled, the force must

be .

1 answer:

LiRa [457]4 years ago

7 0

If both the net force and the mass are doubled, the acceleration will be unchanged.

You might be interested in

explain the relationship between kinetic and potential energy in the example (the pic) while using the words mechanical energy a

BigorU [14]

PE is the energy acquired by a body due to its height ! While KE is the energy acquired by the body due to its motion !

KE+PE = mechanical energy and thus mechanical energy is always conserved due to the conservation of energy which states that energy is neither created nor destroyed but only transformed !

5 0

4 years ago

A. Draw the electric field lines around a negative charge.

Alborosie

<h2>a. Answer:</h2>

We use Electric field lines for visualizing electric fields, so this helps us to see the problem more real. So an electric field line is an imaginary line or curve drawn through a region of space such that the tangent at any point comes from the direction of the electric-field vector at that point. The electric field lines around a negative charge is shown in the First figure below.

<h2>b. Answer:</h2>

Electric forces can be found by using the Coulomb Law's that states <em>that The magnitude of the electric force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. </em>This can be expressed as follows:

$F=k\frac{\left | q_{1}q_{2} \right |}{r^2} \\ \\ Where: \\ \\ k=9\times 10^9Nm^2/c^2 \\ \\ q_{1}=0.00150 C \ and \ q_{2}=0.00240 C \\ \\ r=0.900 m$

Then:

$F=9\times 10^9\frac{\left | 0.00150 \times 0.00240 \right |}{(0.900)^2} \\ \\ \therefore \boxed{F=40000N}$

This force is repulsive because the two charges are positive and recall that two positive charges or two negative charges repel each other while a positive charge and a negative charge attract each other.

<h2>C. Answer:</h2>

From the statement, we have two charged objects. Let's say that this charges are:

$q_{1} \ and \ q_{2}$

If the amount of charge on one of the objects is tripled, let's say this is the charge $q_{2}$ , then the new charge is:

$q_{N}=3q_{2}$

In the formula of Coulomb:

$F=k\frac{\left | q_{1}q_{N} \right |}{r^2} \\ \\ \therefore F=k\frac{\left | q_{1}(3q_{2}) \right |}{r^2} \\ \\ \therefore \boxed{F=3k\frac{\left | q_{1}q_{2} \right |}{r^2}}$

<em>The conclusion is that if the amount of charge on one of the objects is tripled, the electric force between two charged objects is also tripled</em>

<h2>d. Answer:</h2>

Let's use the Coulomb's Law again to solve this problem. We want to know how the electric force between two charged objects changes if the charges are moved closer together:

$F=k\frac{\left | q_{1}q_{N} \right |}{r^2}$

<em>By saying that the charges are moved closer together, we want to express that r becomes smaller. Since r is in the denominator, this implies that the electric force between these two charged objects becomes greater.</em>

<h2>e. Answer:</h2>

From the figure, we can see a metal sphere on a stand. There we have both positive and negative charges. We can say that the positive charge of this sphere is +10q and the negative and the negative charge is -10q. Since the electric charge is conserved, then the algebraic sum of all the electric charges in any closed system is constant. In conclusion, <em>the sphere has no net charge.</em>

<h2>f. Answer:</h2>

Here we want to know how the negative charges in the same sphere are redistributed when a positively charged rod is brought near it. Therefore, positive charge on rod repels positive charges on the sphere, creating zones of negative and positive charge as indicated in the second Figure.

7 0

3 years ago

Read 2 more answers

Why does apparent depth of different liquids vary

Anvisha [2.4K]

It’s due to the refraction of light rays as they traverse the boundary between water and air. The greater the viewing angle, the more the bending of the light and therefore the less the apparent depth. An object placed in a denser medium, when viewed from rarer medium appears to be at a lesser depth than its real depth due to refraction of light.

6 0

4 years ago

a the average distance from the Sun to Pluto is approximately 6.10 x 1 0 ^9. how long does it take light from the sun to reach P

Alex73 [517]

6.10 x 10^9 / 3 x 10^5 = 2.033 x 10^4 seconds = 20.33 / 3.6 = nearly 6 hours .

8 0

4 years ago

Hydraulic systems utilize Pascal's principle by transmitting pressure from one cylinder (called the primary) to another (called

Svetradugi [14.3K]

Answer:

The force to be applied on the primary piston is 140.63 N.

Explanation:

To solve this problem we apply the following formulas:

Pascal principle: F=P*A Formula (1)

F=Force applied to the piston

P: Pressure

A= Piston area

$A=\frac{\pi*d^{2} }{4}$ Formula (2)

d= piston diameter

Nomenclature:

Fp= Force on the primary piston

Fs= Force on the secondary piston

Ap= Primary piston area

As= Secondary piston area

W= car weight

Calculation of the force Fp necessary to support the weight of the car.

Pascal principle: Fp=P*Ap (Equation1)

In (Equation1) we know Ap and we don't know P.

Pressure calculation:

We apply Newton's first law for a balanced Secondary piston -automobile system

Newton's first law: ∑F=0

W-Fs=0

W=Fs

W=P*As

$P=\frac{W}{As}$

We replace $P=\frac{W}{As}$ in equation 1:

$Fp=\frac{W}{As} *Ap$

$Fp=\frac{W}{\frac{\pi*d_{s}^{2} }{4} } *\pi *\frac{d_{p^{2} } }{4}$

$Fp=W*\frac{d_{p}^{2} }{d_{s}^{2} }$

$Fp=2200*\frac{2,1^{2} }{26^{2} }$

$Fp=2200*\frac{4.41}{676}$

$Fp=14.35kg$

Calculation of Fp in Newtons (N):

$1kg=9.8N$

$Fp=14.35kg*\frac{9.8N}{kg}$

Fp=140.63N

3 0

3 years ago