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-Dominant- [34]

3 years ago

11

I am one of the most dynamic processes of Earth. I help recycle Earth's materials. I move Earth's crustal plates, creating many

different geological surface features. I am also the cause of natural disasters, such as earthquakes and volcanoes. What am I?

2 answers:

Sergio039 [100]3 years ago

7 0

I Can only think of tectonic plates or gravity

spayn [35]3 years ago

5 0

Continental Drift.. ✌

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How does an atom of rubidium-85 become a rubidium ion with a +1 charge?

Nastasia [14]

Answer:

C. The atom loses 1 electron to have a total of 36.

Explanation:

Cations have a positive charge. Cations lose electrons.

The number of electrons in a Rubidium atom is 37. If the atom loses 1 electron, then it has 36 left.

6 0

3 years ago

One day, after pulling down your window shade, you notice that sunlight is passing through a pinhole in the shade and making a s

DedPeter [7]

Complete Question

One day, after pulling down your window shade, you notice that sunlight is passing through a pinhole in the shade and making a small patch of light on the far wall. Having recently studied optics in your physics class, you're not too surprised to see that the patch of light seems to be a circular diffraction pattern. It appears that the central maximum is about 2 cm across, and you estimate that the distance from the window shade to the wall is about 5 m.

Required:

Estimate the diameter of the pinhole.

Answer:

The diameter is $d =0.000336 m$

Explanation:

From the question we are told that

The central maxima is $D= 2cm = \frac{2}{100} = 0.02m$

The distance from the window shade is $L = 5m$

The average wavelength of the sun is mathematically evaluated as

$\lambda_{ave } = \frac{\lambda_i + \lambda_f}{2}$

Generally the visible light spectrum has a wavelength range between 400 nm to 700 nm

So the initial wavelength of the sun is $\lambda _i = 400nm$

and the final wavelength is $\lambda_f = 700nm$

Substituting this into the above equation

$\lambda_{sun} = \frac{400nm +700nm}{2}$

$= 550nm$

The diameter is evaluated as

$d = \frac{2.44 \lambda_{sun} L}{D}$

substituting values

$d = \frac{2.44 * 550*10^{-9} * 5 }{0.02}$

$d =0.000336 m$

5 0

3 years ago

Based on the TIA/EIA 568-B structured cabling standard, the cabling that runs from the telecommunications closet to each work ar

lana [24]

Answer:

False.

Explanation:

Backbone Cabling: A system of cabling that connects the equipment rooms and telecommunications rooms.

Horizontal Cabling: The system of cabling that connects telecommunications rooms to individual outlets or work areas on the floor.

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3 years ago

How does tightening a string on a guitar affect its natural frequency?

iragen [17]

By tightening a string you are actually putting more stress on the string you are giving it a new frequency that isn't natural.

Hope this helps
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3 0

3 years ago

Read 2 more answers

A man walks along a straight path at a speed of 4 ft/s. A searchlight is located on the ground 6 ft from the path and is kept fo

BARSIC [14]

We are given that,

$\frac{dx}{dt} = 4ft/s$

We need to find $\frac{d\theta}{dt}$ when $x=8ft$

The equation that relates x and $\theta$ can be written as,

$\frac{x}{6} tan\theta$

$x = 6tan\theta$

Differentiating each side with respect to t, we get,

$\frac{dx}{dt} = \frac{dx}{d\theta} \cdot \frac{d\theta}{dt}$

$\frac{dx}{dt} = (6sec^2\theta)\cdot \frac{d\theta}{dt}$

$\frac{d\theta}{dt} = \frac{1}{6sec^2\theta} \cdot \frac{dx}{dt}$

Replacing the value of the velocity

$\frac{d\theta}{dt} = \frac{1}{6} cos^2\theta (4)^2$

$\frac{d\theta}{dt} = \frac{8}{3} cos^2\theta$

The value of $cos \theta$ could be found if we know the length of the beam. With this value the equation can be approximated to the relationship between the sides of the triangle that is being formed in order to obtain the numerical value. If this relation is known for the value of x = 6ft, the mathematical relation is obtained. I will add a numerical example (although the answer would end in the previous point) If the length of the beam was 10, then we would have to

$cos\theta = \frac{6}{10}$

$\frac{d\theta}{dt} = \frac{8}{3} (\frac{6}{10})^2$

$\frac{d\theta}{dt} = \frac{24}{25}$

Search light is rotating at a rate of 0.96rad/s

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3 years ago