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-Dominant- [34]

4 years ago

11

I am one of the most dynamic processes of Earth. I help recycle Earth's materials. I move Earth's crustal plates, creating many

different geological surface features. I am also the cause of natural disasters, such as earthquakes and volcanoes. What am I?

2 answers:

Sergio039 [100]4 years ago

7 0

I Can only think of tectonic plates or gravity

spayn [35]4 years ago

5 0

Continental Drift.. ✌

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Please do all of i will give you brainlest and thanks to best answer

vlabodo [156]

Answer:the answer is A

Explanation:

3 0

3 years ago

You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics

spayn [35]

Answer:

$v_0 = 3.53~{\rm m/s}$

Explanation:

This is a projectile motion problem. We will first separate the motion into x- and y-components, apply the equations of kinematics separately, then we will combine them to find the initial velocity.

The initial velocity is in the x-direction, and there is no acceleration in the x-direction.

On the other hand, there no initial velocity in the y-component, so the arrow is basically in free-fall.

Applying the equations of kinematics in the x-direction gives

$x - x_0 = v_{x_0} t + \frac{1}{2}a_x t^2\\63 \times 10^{-3} = v_0t + 0\\t = \frac{63\times 10^{-3}}{v_0}$

For the y-direction gives

$v_y = v_{y_0} + a_y t\\v_y = 0 -9.8t\\v_y = -9.8t$

Combining both equation yields the y_component of the final velocity

$v_y = -9.8(\frac{63\times 10^{-3}}{v_0}) = -\frac{0.61}{v_0}$

Since we know the angle between the x- and y-components of the final velocity, which is 180° - 2.8° = 177.2°, we can calculate the initial velocity.

$\tan(\theta) = \frac{v_y}{v_x}\\\tan(177.2^\circ) = -0.0489 = \frac{v_y}{v_0} = \frac{-0.61/v_0}{v_0} = -\frac{0.61}{v_0^2}\\v_0 = 3.53~{\rm m/s}$

6 0

3 years ago

A rectangle has a length of (2.5 ± 0.2) m and a width of (1.5 ± 0.2) m. Calculate the area and the perimeter of the rectangle, a

eduard

You can just add the uncertainties

5 0

2 years ago

What is the magnitude of the change in potential energy of the block-spring system when it travels from its lowest vertical posi

maksim [4K]

Answer:

ΔU = 2 mg h

Explanation:

In a spring mass system the potential energy is U = m g h

where h is measured from the equilibrium point of the spring

the potential energy at the highest point is

U₁ = m g h

the potential energy at the lowest point is

U₂ = m g (-h)

instead in this energy it is

ΔU = 2 mg h

In this two points the kinetic energy is zero, but there is elastic potential energy that has the same value in the two points, so its change is zero

4 0

3 years ago

An ideal battery would produce an extraordinarily large current if "shorted" by connecting the positive and negative terminals w

liubo4ka [24]

Answer:

Resistance, $R=0.529\ \Omega$

Explanation:

Given that,

Voltage of the battery, V = 9 volts

Current produced in the circuit, I = 17 A

We need to find the resistance when shorted by a wire of negligible resistance. It is a case of Ohm's law. The voltage is given by :

$V=IR$

$R=\dfrac{V}{I}$

$R=\dfrac{9\ V}{17\ A}$

$R=0.529\ \Omega$

So, the resistance in the circuit is 0.529 ohms. Hence, this is the required solution.

6 0

3 years ago