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-Dominant- [34]
3 years ago
11

I am one of the most dynamic processes of Earth. I help recycle Earth's materials. I move Earth's crustal plates, creating many

different geological surface features. I am also the cause of natural disasters, such as earthquakes and volcanoes. What am I?
Physics
2 answers:
Sergio039 [100]3 years ago
7 0

I Can only think of tectonic plates or gravity
spayn [35]3 years ago
5 0

Continental Drift.. ✌

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Assuming a vertical trajectory with no drag, derive the applicable form of the rocket equation for this application
VARVARA [1.3K]

Answer:

The vertical trajectory is governed by Ordinary Differential Equation.

Time derivatives of each state variables.

d(d)/dt = v, d(m)/dt = -d(m-fuel)/dt, d(v)/dt = F/m.

Where V is velocity positive upwards, t is time, m is mass, m-fuel is fuel mass, F is Total force, positive upwards.

Therefore,

F = -mg - D + T, If V is positive and

F = -mg + D - T, If T is negative.

D is drag and the questions gave it as zero.

Explanation:

The two sign cases in derivative equations above are required because F is defined positive up, so the drag D and thrust T can subtract or add to F depending in the sign of V . In contrast, the gravity force contribution mg is always negative. In general, F will be some function of time, and may also depend on the characteristics of the particular rocket. For example, the T component of F will become zero after all the fuel is expended, after which point the rocket will be ballistic, with only the gravity force and the aerodynamic drag force being p

8 0
3 years ago
A student wants to determine the impulse delivered to the lab cart when it runs into the wall. The student measures the mass of
forsale [732]
Impulse = Force * times and also Impulse = change in momentum.

Given that the mass does not change, change if momentum = mass * (final velocity -  initial velocity)

Given that you know mass and initial velocity (which is the velicity before the cart hits the wall) you need the final velocity (which is the velocity after the cart hits the wall).

Answer: the velocity of the cart after it hits the wall.
6 0
3 years ago
A professional golfer hits a golf ball of mass 46 g with her 5-iron, and the ball first strikes the ground 155 m away. The ball
RideAnS [48]

Answer:

C=2.32\times 10^{-4}\ Ns^2/m^2

Explanation:

It is given that,

Mass of the golf ball, m = 46 g = 0.046 kg

Terminal speed of the ball, v = 44 m/s

The drag force, F_r=Cv^2

Where, C is the drag coefficient. At terminal speed, the weight of the ball is balanced by the drag force.

Cv^2=mg

C=\dfrac{mg}{v^2}

C=\dfrac{0.046\times 9.8}{(44)^2}

C=2.32\times 10^{-4}\ Ns^2/m^2

Hence, this is the required solution.

4 0
3 years ago
An object has a mass of 10 kilograms and is accelerating at 5 m/s/s, what force pushed the object?
Katen [24]

Answer:

force pushed the object = 10 × 5 = 50N

8 0
3 years ago
Newton concluded that some force had to act on the moon because
Dimas [21]
Think in gravity, the moon is orbiting the Earth because of gravitational pull/force. Without this gravitational pull, the moon will just move in a straight line (Newton's first law).
6 0
3 years ago
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