Let the key is free falling, therefore from equation of motion
.
Take initial velocity, u=0, so
.
![h = 0\times t + \frac{1}{2}g t^2= \frac{1}{2}gt^2 \\\ t =\sqrt{\frac{2h}{g} }](https://tex.z-dn.net/?f=h%20%3D%200%5Ctimes%20t%20%2B%20%5Cfrac%7B1%7D%7B2%7Dg%20t%5E2%3D%20%5Cfrac%7B1%7D%7B2%7Dgt%5E2%20%5C%5C%5C%20t%20%3D%5Csqrt%7B%5Cfrac%7B2h%7D%7Bg%7D%20%7D)
As velocity moves with constant velocity of 3.5 m/s, therefore we can use formula
![d= v \times t](https://tex.z-dn.net/?f=d%3D%20v%20%5Ctimes%20t)
From above substituting t,
.
Now substituting all the given values and g = 9.8 m/s^2, we get
.
Thus, the distance the boat was from the point of impact when the key was released is 10.60 m.
Lear vv
F
B
C
D
A
E
G
greatest pressure ^^
I’m really sorry if I’m wrong
Answer:
less than stating velocity due to friction and air resistance.
Explanation:
Answer:
Explanation:
solid
This type of matter is know as solid. Also, it is known that solid substances have definite shape and volume. Thus, we can conclude that a substance with a definite shape and volume is a solid phase of matter.