ANSWER
![\begin{equation*} 4.67*10^{-9}\text{ }N \end{equation*}](https://tex.z-dn.net/?f=%5Cbegin%7Bequation%2A%7D%204.67%2A10%5E%7B-9%7D%5Ctext%7B%20%7DN%20%5Cend%7Bequation%2A%7D)
EXPLANATION
Parameters given:
Mass of the student, M = 70 kg
Mass of the textbook, m = 1 kg
Distance, r = 1 m
To find the gravitational force acting between the student and the textbook, apply the formula for gravitational force:
![F=\frac{GMm}{r^2}](https://tex.z-dn.net/?f=F%3D%5Cfrac%7BGMm%7D%7Br%5E2%7D)
where G = gravitational constant
Therefore, the gravitational force acting between the student and the textbook is:
![\begin{gathered} F=\frac{6.67430*10^{-11}*70*1}{1^2} \\ \\ F=4.67*10^{-9}\text{ }N \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20F%3D%5Cfrac%7B6.67430%2A10%5E%7B-11%7D%2A70%2A1%7D%7B1%5E2%7D%20%5C%5C%20%20%5C%5C%20F%3D4.67%2A10%5E%7B-9%7D%5Ctext%7B%20%7DN%20%5Cend%7Bgathered%7D)
That is the answer.
Solution :
Given :
Mass attached to the spring = 4 kg
Mass dropped = 6 kg
Force constant = 100 N/m
Initial amplitude = 2 m
Therefore,
a). ![$v_{initial} = A w$](https://tex.z-dn.net/?f=%24v_%7Binitial%7D%20%3D%20A%20w%24)
![$= 2 \times \sqrt{\frac{100}{4}}$](https://tex.z-dn.net/?f=%24%3D%202%20%5Ctimes%20%5Csqrt%7B%5Cfrac%7B100%7D%7B4%7D%7D%24)
= 10 m/s
Final velocity, v at equilibrium position, v = 5 m/s
Now, ![$\frac{1}{2}(4+4)5^2 = \frac{1}{2} kA'$](https://tex.z-dn.net/?f=%24%5Cfrac%7B1%7D%7B2%7D%284%2B4%295%5E2%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20kA%27%24)
A' = amplitude = 1.4142 m
b). ![$T=2 \pi \sqrt{\frac{m}{k}}$](https://tex.z-dn.net/?f=%24T%3D2%20%5Cpi%20%5Csqrt%7B%5Cfrac%7Bm%7D%7Bk%7D%7D%24)
m' = 2m
Hence, ![$T'=\sqrt2 T$](https://tex.z-dn.net/?f=%24T%27%3D%5Csqrt2%20T%24)
c). ![$\frac{\frac{1}{2}(4+4)5^2 + \frac{1}{2}\times 4 \times 10^2}{\frac{1}{2} \times 4 \times 10^2}$](https://tex.z-dn.net/?f=%24%5Cfrac%7B%5Cfrac%7B1%7D%7B2%7D%284%2B4%295%5E2%20%2B%20%5Cfrac%7B1%7D%7B2%7D%5Ctimes%204%20%5Ctimes%2010%5E2%7D%7B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%204%20%5Ctimes%2010%5E2%7D%24)
![$=\frac{1}{2}$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B1%7D%7B2%7D%24)
Therefore, factor ![$=\frac{1}{2}$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B1%7D%7B2%7D%24)
Thus, the energy will change half times as the result of the collision.
u have not displayed the question fella but i can guess the answer
Explanation:
the answer is (i)
because the current in a circuit is always directly proportional to its voltage thus making it to make a straight line in its graph
Answer:
Explanation: Determine the gravitational acceleration. ...
Decide whether the object has an initial velocity. ...
Choose how long the object is falling. ...
Calculate the final free fall speed (just before hitting the ground) with the formula v = v₀ + gt
B. so light can shine through it from below.