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saveliy_v [14]
2 years ago
15

What does a snow leopard eat?

Physics
1 answer:
Rom4ik [11]2 years ago
4 0

Answer:

They eat Himalayan blue sheep, boar, deers, wild mountain goats, pikas etc.

Explanation:

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3. Sailors use a capstan (shown below) to raise and lower the anchor. It takes two sailors located 1 meter from the center to tu
mr_godi [17]

Answer:

B. 2 meters.

Explanation:

To rotate the capstan a certain amount of torque is required, and if each sailor applies a force F at a distance D from the center, then for two sailors the total torque will be

\tau = 2FD\\;

therefore,  for one sailor to apply the same torque it must be that the torque \tau_2 he applies must be equal to the torque that the two sailors applied:

FD_2 =2FD

which gives

D_2 = 2D.

and since D = 1\:meter,

\boxed{D_2 = 2\: meters}

which is choice B.

4 0
3 years ago
(a) In what direction would the ship in Exercise 3.57 have to travel in order to have a velocity straight north relative to the
shtirl [24]

Answer:

Direction of ship: 9.45° West of North

Ship's relative speed: 7.87m/s

Explanation:

A. Direction of ship: since horizontal of the velocity of boat relative to the ground is 0

Vx=0

Therefore, -VsSin∅+VcCos∅40°

Sin∅ = Vc/Vs × Cos 40°

Sin∅ = 1.5/7 ×Cos40°

Sin∅= 0.164

∅= Sin-¹ (0.164)

∅= 9.45° W of N

B. Ship's relative speed:

Vy= VsCos∅ + Vcsin40°

= 7Cos9.45° + 1.5sin40°

= 7×0.986 + 1.5×0.642

= 7.865

= 7.87m/s

4 0
3 years ago
What 2 events increase power output
OverLord2011 [107]
P=I*E
Power (P)
Voltage (E)
Amps (I)

7 0
3 years ago
Read 2 more answers
Two ropes are attached to a 40-kg object. The first rope applies a force of 50 N and the second, 40 N. If the two ropes are perp
Montano1993 [528]

To solve this problem we will use the concepts related to the resulting Vector Force product of two components, that is,

|\vec{F}| = \sqrt{F_x^2+F_y^2}

If we take the Force of 50 N as the force in the X direction and the Force of 40 N in the Y direction we will have to:

|\vec{F}| = \sqrt{F_x^2+F_y^2}

|\vec{F}| = \sqrt{(50)^2+(40)^2}

|\vec{F}| = 64.03N

Finally, since Newton's second law, acceleration can be determined as

F = ma

a = \frac{F}{m}

a = \frac{ 64.03}{40}

a = 1.6m/s^2

Therefore the resultant magnitude of the acceleration of the object is 1.6m/s^2

4 0
3 years ago
Which of the following is a FALSE statement about acceleration? A. Acceleration can be zero, positive, or negative. B. An object
olchik [2.2K]
<h3><u>Answer</u>;</h3>

C. An object can have acceleration with negative velocity.

<h3><u>Explanation</u>;</h3>
  • Acceleration is a measure of the change in velocity over time. The change in velocity is measured in meter per second (m/s), and time interval is measured in second (s).
  • Therefore, acceleration measures the change in meters per second every second [(m/s)/s], namely meters per second per second or meters per second squared (m/s2).
  • If an object has zero acceleration, its velocity doesn’t have to be zero. Acceleration is a measure of the change in velocity over time. Zero acceleration means there is no change in velocity over time, namely constant velocity.
6 0
3 years ago
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