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ivanzaharov [21]
3 years ago
12

Theoretically, how far away from the Earth do you have to go to feel zero gravitational force from the Earth?

Chemistry
2 answers:
EastWind [94]3 years ago
5 0

Answer:

B because you will feel the moons gravitational force and not earths

Hope it helps

Explanation:

slavikrds [6]3 years ago
3 0

Answer:

This is a trick question, as to feel zero gravitational force you just have to leave about half of the earths radius, so id guess it would be B.

Explanation:

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What is scientific observation
prisoha [69]

Answer:

Getting knowledge from the outside world with our senses, and scientific tools.

Explanation:

(e.g. a doctor watched a patient after giving them a. vaccine)

8 0
3 years ago
In the reaction MgCl2 + 2KOH → Mg(OH)2 + 2KCI, how many grams of KOH
dsp73

Answer:

The correct option is;

D. (2)(56 g)

Explanation:

MgCl₂ + 2KOH → Mg(OH)₂ + 2KCl

From the balanced chemical reaction equation, we have;

One mole of MgCl₂ reacts with  two moles of KOH to produce one mole of Mg(OH)₂ and 2 moles of KCl

Therefore, the number of moles of KOH that react with one mole of KCl = 2 moles

The mass, m, of the two moles of KOH = Number of moles of KOH × Molar mass of KOH

The molar mass of KOH = 56.1056 g/mol

∴ The mass, m, of the two moles of KOH = 2 moles × 56.1056 g/mol = 112.2112 grams

The amount in grams of KOH that react with one mole of MgCl₂ = 112.2112 grams ≈ 112 grams =  (2)(56 g).

4 0
3 years ago
The following anions can be separated by precipitation as silver salts: Cl- , Br- , I- , CrO4 2-. If Ag is added to a solution c
dalvyx [7]

Answer:

AgI, AgBr, AgCl and Ag₂CrO₄

Explanation:

Ksp (product solubility constant) is defined as the equilibrium constant of the general reaction:

XₐYₙ(s) → aXⁿ⁺(aq) + nYᵃ⁻(aq)

<em>Where X is cation and Y is anion.</em>

Ksp = [aXⁿ⁺]ᵃ [nYᵃ⁻]ⁿ

The presence of XₐYₙ(s) produce ax moles of aXⁿ⁺ and nx moles of Yᵃ⁻. <em>Where X is the solubility of the compound.</em>

Replacing in Ksp:

Ksp = [ax]ᵃ [nx]ⁿ

Solving for x, Solubility (S) is defined as:

S = \sqrt[n+a]{\frac{Ksp}{a^{a} n^n} }

For AgCl, Ag₂CrO₄, AgBr and AgI solubilities are:

S = \sqrt[2]{\frac{1.8x10^{-10}}{1} } = 1.34x10⁻⁵M

S = \sqrt[3]{\frac{1.1x10^{-12}}{4} } = 6.50x10⁻⁵M

S = \sqrt[2]{\frac{5.4x10^{-13}}{1} } = 7.35x10⁻⁷M

S = \sqrt[2]{\frac{8.5^{-17}}{1} } = 9.22x10⁻⁹M

The lower solubility is the first compound in precipitate, thus, order of precipitation is:

<em>AgI, AgBr, AgCl and Ag₂CrO₄</em>

8 0
3 years ago
Calculate the pH of a 0.0350M
Triss [41]

Answer:

pH = 12.544

Explanation:

  • NaOH   →    Na+      +     OH-

     0.0350M   0.0350M    0.0350M.........equilibrium

∴ pOH = - log [OH-]

∴ pH + pOH = 14

⇒ [OH-] = 0.0350 M

⇒ pOH = - Log (0.0350)

⇒ pOH = 1.456

⇒ pH = 14 - 1.456

⇒ pH = 12.544

6 0
3 years ago
Read 2 more answers
What are mettaloids? ​
julia-pushkina [17]

Answer:

Los metaloides serían los elementos con propiedades intermedias. No existe una definición estandarizada de elemento metaloide ni un consenso completo sobre los elementos que son metaloides. A pesar de la falta de especificidad en el término, es muy utilizado en los textos químicos, tanto educativos como divulgativos o de investigación.

Explanation:

6 0
2 years ago
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