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mariarad [96]
3 years ago
10

Given the velocity function v of an object moving along a​ line, explain how definite integrals can be used to find the displace

ment of the object
Physics
1 answer:
Sati [7]3 years ago
8 0

Answer:

Expression of displacement will be s(t)=\int_{t_0}^{t}v(t)dt

Explanation:

Let the velocity v(t) is function of time means when time changes then velocity also changes

We have to find the expression of definite integral to find the displacement

Displacement is ti,e integral of velocity in given period of time

Let the object starts moving at time t=t_0 and move to the time t=t

Then displacement is give by

s(t)=\int_{t_0}^{t}v(t)dt

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A group of hikers hear an echo 3.3 s after they shout. The temperature is 20◦C.
romanna [79]

Answer:

560 m

Explanation:

The speed of sound in air is approximately:

v ≈ v₀ + 0.6T

where v₀ is the speed of sound at 0°C (273 K) in m/s, and T is the temperature in Celsius.

The speed of sound at 20°C at that altitude is:

v ≈ 327 + 0.6(20)

v ≈ 339 m/s

The sound travels from the hikers to the mountain and back again, so it travels twice the distance.

339 m/s = 2d / 3.3 s

2d = 1118.7 m

d = 559.35 m

Rounding, the mountain is approximately 560 m away.

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What is the SI unit for momentum?
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It’s a vector quantity, which means it possesses both magnitude and direction. So the SI unit would be B)kg•m/s
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Which statement about electrons and atomic orbitals is not true?
Lubov Fominskaja [6]

An electron cloud represents all the orbitals in an atom.

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Which biome has the most variable year round temperature
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That should be the Grasslands ?
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The site from which an airplane takes off is the origin. The X axis points east, the y axis points straight up. The position and
Contact [7]

Answer:

d = 3.5*10^4 m

Explanation:

In order to calculate the displacement of the airplane you need only the information about the initial position and final position of the airplane. THe initial position is at the origin (0,0,0) and the final position is given by the following vector:

\vec{r}=(1.21*10^3\hat{i}+3.45*10^4\hat{j})m

The displacement of the airplane is obtained by using the general form of the Pythagoras theorem:

d=\sqrt{(x-x_o)^2+(y-y_o)^2}   (1)

where x any are the coordinates of the final position of the airplane and xo and yo the coordinates of the initial position. You replace the values of all variables in the equation (1):

d=\sqrt{(1.12*10^3-0)^2+(3.45*10^4-0)^2}=3.45*10^4m

hence, the displacement of the airplane is 3.45*10^4 m

6 0
3 years ago
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