With what magnitude of force does a ball of mass 0.75 kilograms need to be hit so that it accelerates at the rate of 25 meters/s
2 answers:
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Answer:
The positions are 0.0194 m and - 0.0194 m.
Explanation:
Given;
amplitude of the simple harmonic motion, A = 2.0 cm = 0.02 m
speed of simple harmonic motion is given as;
the maximum speed of the simple harmonic motion is given as;
when the speed equal one fourth of its maximum speed
Thus, the positions are 0.0194 m and - 0.0194 m.
The frequencies are missing in the question. The three successive resonance frequencies within the volume are .
Solution :
Let the volume be : v
The frequency for one end open and one end closed is given by :
So,
Therefore,
,
,
So, and
Therefore, the ratio of which is not a whole number.
Now the frequency for open volume and closed at both end
So, ,
,
From above formulae we can see that ratio of is not a whole number that is a identification for the frequency of the volume at one end open and one end closed.
Also ratio of the consecutive frequency of the volume at open from both side and closed from both side is always a whole number.