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Brut [27]
3 years ago
12

With what magnitude of force does a ball of mass 0.75 kilograms need to be hit so that it accelerates at the rate of 25 meters/s

econd2? Assume that the ball undergoes motion along a straight line
Physics
2 answers:
serious [3.7K]3 years ago
8 0

     Force = (mass) x (acceleration)

               = (0.75 kg) x (25 m/s²)

               =  (0.75 x 25)  kg-m/s²

               =    18.75 newtons .

Note that even though we're talking about a 'hit', the acceleration only
lasts as long as the bat is in contact with the ball.  Once the ball leaves
the bat, it travels at whatever speed it had at the instant when they parted. 
Any change in its speed or direction after that is the result of gravity, air
resistance, and the fielder's mitt.  I learned a lot about these things a few
weeks ago, since I live in Chicago, about 6 miles from Wrigley Field, in
a house full of Cubs fans.
S_A_V [24]3 years ago
6 0

Answer:

answer is B 19 newtons for plato users

Explanation:

got 100% on test, the other answer explains the method pretty well

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F = 2.34 x 10^-3 N
Answer is B.

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8 0
3 years ago
Explain why convex mirrors can only produce virtual images. Please use at least 2 content related sentences. (ref: p.471-481)
34kurt

Convex mirrors can only produce virtual images because the focal point and the center of curvature of the convex mirror are imaginary points and that cannot be reached.

<h3>What is virtual image?</h3>

This is referred to the opposite of a real image and cannot be obtained on a screen. It is formed from the  apparent divergent of light rays from a point  and not the actual one which is the major difference it has with a real image.

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Read more about Convex mirrors here brainly.com/question/14269744

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8 0
1 year ago
Which term describes the amount of water vapor in the air?
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That would be humidity
4 0
3 years ago
Read 2 more answers
The smallest shift you can reliably measure on the screen is about 0.2 grid units. This shift corresponds to the precision of po
creativ13 [48]

Answer:

The distance is  d = 1.5 *10^{15} \ km

Explanation:

From the question we are told that

        The smallest shift is d = 0.2 \ grid \ units

Generally a grid unit is  \frac{1}{10} of  an arcsec

  This implies that  0.2 grid unit is  k =  \frac{0.2}{10} = 0.02  \  arc sec

The maximum distance at which a star can be located and still have a measurable parallax is mathematically represented as

           d =  \frac{1}{k}

substituting values

           d =  \frac{1}{0.02}

           d = 50 \ parsec

Note  1 \ parsec  \ \to 3.26 \ light \ year \ \to 3.086*10^{13} \ km

So  d = 50 * 3.08 *10^{13}

     d = 1.5 *10^{15} \ km

3 0
3 years ago
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