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Brut [27]
3 years ago
12

With what magnitude of force does a ball of mass 0.75 kilograms need to be hit so that it accelerates at the rate of 25 meters/s

econd2? Assume that the ball undergoes motion along a straight line
Physics
2 answers:
serious [3.7K]3 years ago
8 0

     Force = (mass) x (acceleration)

               = (0.75 kg) x (25 m/s²)

               =  (0.75 x 25)  kg-m/s²

               =    18.75 newtons .

Note that even though we're talking about a 'hit', the acceleration only
lasts as long as the bat is in contact with the ball.  Once the ball leaves
the bat, it travels at whatever speed it had at the instant when they parted. 
Any change in its speed or direction after that is the result of gravity, air
resistance, and the fielder's mitt.  I learned a lot about these things a few
weeks ago, since I live in Chicago, about 6 miles from Wrigley Field, in
a house full of Cubs fans.
S_A_V [24]3 years ago
6 0

Answer:

answer is B 19 newtons for plato users

Explanation:

got 100% on test, the other answer explains the method pretty well

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lord [1]

(a) 3675 N

Assuming that the acceleration of the rocket is in the horizontal direction, we can use Newton's second law to solve this part:

F_x = m a_x

where

F_x is the horizontal component of the force

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a_x is the horizontal component of the acceleration

Here we have

m = 75.0 kg

a_x = 49.0 m/s^2

Substituting,

F_x=(75.0)(49.0)=3675 N

(b) 3748 N, 11.3 degrees above horizontal

In this part, we also have to take into account the forces acting along the vertical direction. In fact, the seat exerts a reaction force (R) which is equal in magnitude and opposite in direction to the weight of the passenger:

R=mg=(75.0)(9.8)=735 N

where we used

g=9.8 m/s^2 as acceleration of gravity.

So, this is the vertical component of the force exerted by the seat on the passenger:

F_y = 735 N

and therefore the magnitude of the net force is

F=\sqrt{F_x^2+F_y^2}=\sqrt{3675^2+735^2}=3748 N

And the direction is given by

\theta = tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{735}{3675})=11.3^{\circ}

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3 years ago
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Answer:

Explanation:

Given

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radius R

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