Answer:

Explanation:
1. pH of original buffer
(a) Calculate pKₐ

(b) Calculate the pH
We can use the Henderson-Hasselbalch equation to get the pH.
![\begin{array}{rcl}\text{pH} & = & \text{pK}_{\text{a}} + \log \left(\dfrac{[\text{A}^{-}]}{\text{[HA]}}\right )\\\\& = & 7.54 +\log \left(\dfrac{0.450}{0.450}\right )\\\\& = & 7.54 + \log1.00 \\ & = & 7.54 + 0.00\\& = & 7.54\\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7D%5Ctext%7BpH%7D%20%26%20%3D%20%26%20%5Ctext%7BpK%7D_%7B%5Ctext%7Ba%7D%7D%20%2B%20%5Clog%20%5Cleft%28%5Cdfrac%7B%5B%5Ctext%7BA%7D%5E%7B-%7D%5D%7D%7B%5Ctext%7B%5BHA%5D%7D%7D%5Cright%20%29%5C%5C%5C%5C%26%20%3D%20%26%207.54%20%2B%5Clog%20%5Cleft%28%5Cdfrac%7B0.450%7D%7B0.450%7D%5Cright%20%29%5C%5C%5C%5C%26%20%3D%20%26%207.54%20%2B%20%5Clog1.00%20%5C%5C%20%26%20%3D%20%26%207.54%20%2B%200.00%5C%5C%26%20%3D%20%26%207.54%5C%5C%5Cend%7Barray%7D)
2. pH after adding strong base
(a) Find new composition of the buffer
The base reacts with the HA and forms A⁻

HA + OH⁻ ⟶ A⁻ + H₂O
I/mmol: 450 40 450
C/mmol: -40 -40 40
E/mmol: 410 0 490
(b) Find the new pH
![\begin{array}{rcl}\text{pH} & = & \text{pK}_{\text{a}} + \log \left(\dfrac{[\text{A}^{-}]}{\text{[HA]}}\right )\\\\& = & 7.54 +\log \left(\dfrac{490}{410}\right )\\\\& = & 7.54 + \log1.195 \\& = & 7.54 +0.0774\\& = & \mathbf{7.62}\\\end{array}\\\text{The new pH is $\large \boxed{\textbf{7.62}}$}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7D%5Ctext%7BpH%7D%20%26%20%3D%20%26%20%5Ctext%7BpK%7D_%7B%5Ctext%7Ba%7D%7D%20%2B%20%5Clog%20%5Cleft%28%5Cdfrac%7B%5B%5Ctext%7BA%7D%5E%7B-%7D%5D%7D%7B%5Ctext%7B%5BHA%5D%7D%7D%5Cright%20%29%5C%5C%5C%5C%26%20%3D%20%26%207.54%20%2B%5Clog%20%5Cleft%28%5Cdfrac%7B490%7D%7B410%7D%5Cright%20%29%5C%5C%5C%5C%26%20%3D%20%26%207.54%20%2B%20%5Clog1.195%20%5C%5C%26%20%3D%20%26%207.54%20%2B0.0774%5C%5C%26%20%3D%20%26%20%5Cmathbf%7B7.62%7D%5C%5C%5Cend%7Barray%7D%5C%5C%5Ctext%7BThe%20new%20pH%20is%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B7.62%7D%7D%24%7D)
Answer:
Methyl Alcohol.
Acetate
Heptane
Dioxane
Explanation:
The boiling point of liquids are measure by observing the gas pressure or vapors temperature. There are few liquids whose boiling point is difficult to measure. The gas pressure differs for every liquid. It is important to observe the vapor pressure also to identify the boiling point. The most difficult boiling point identification is for Methyl alcohol as it has ability to absorb different level of pressure.
i think the answer is A. water flowing downhill and spinning turbines
Answer:
The mass of 1.00 mol of allicin, rounded to the nearest integer, is 162 g
Explanation:
Allicin is a compound that derivates from the alliin which is produced by the catalyzis of an enzime.
The molecular formula is: C₆H₁₀OS₂.
Let's determine the molar mass which is the mass that corresponds to 1 mol
Molar mass C . 6 + Molar mass H . 10 + Molar mass O + Molar mass S . 2 =
12 g/mol . 6 + 1 g/mol . 10 + 16 g/mol + 32.06 g/mol . 2 = 162.1 g/mol