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Anarel [89]
4 years ago
13

At which temperature would a can of soda be most fizzy when it is opened?

Chemistry
2 answers:
kati45 [8]4 years ago
7 0
Answer: at higher temperatures.
Justification:

1) Soda have CO₂ dissolved. Carbonation consists on that: dissolving CO₂ into water, leading to carbonated water.


2) The solution of a gas into a liquid is inversely related to the temperature: the lower the temperature the more gas gets dissolved.
So, in the manufacturing of soda, the CO₂ is added in cool water in a cool environment.


3) So, the higher the temperature after the soda is delivered, the more gas will be liberated when you open the can.

kiruha [24]4 years ago
4 0
The temperature would be 40c
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Enter your answer in the provided box. An industrial chemist studying bleaching and sterilizing prepares a hypochlorite buffer u
neonofarm [45]

Answer:

\large \boxed{7.62}

Explanation:

1. pH of original buffer

(a) Calculate pKₐ

\text{p}K_{\text{a}} = -\log \left (K_{\text{a}} \right ) =-\log(2.9 \times 10^{-8}) = 7.54

(b) Calculate the pH

We can use the Henderson-Hasselbalch equation to get the pH.

\begin{array}{rcl}\text{pH} & = & \text{pK}_{\text{a}} + \log \left(\dfrac{[\text{A}^{-}]}{\text{[HA]}}\right )\\\\& = & 7.54 +\log \left(\dfrac{0.450}{0.450}\right )\\\\& = & 7.54 + \log1.00 \\ & = & 7.54 + 0.00\\& = & 7.54\\\end{array}

2. pH after adding strong base

(a) Find new composition of the buffer

The base reacts with the HA and forms A⁻

\text{ Initial moles of HA} = \text{1.0 L} \times \dfrac{\text{0.450 mol }}{\text{1.00 L}} = \text{0.450 mol = 450 mmol}\\\\\text{ Initial moles of A}^{-} = \text{1.0 L} \times \dfrac{\text{0.450 mol }}{\text{1.00 L}} = \text{0.450 mol = 450 mmol}\\\\\text{Moles of OH$^{-}$ added} = \text{40 mmol}

                 HA     +     OH⁻    ⟶     A⁻ + H₂O

I/mmol:    450            40              450

C/mmol:    -40           -40                 40

E/mmol:    410               0              490

(b) Find the new pH  

\begin{array}{rcl}\text{pH} & = & \text{pK}_{\text{a}} + \log \left(\dfrac{[\text{A}^{-}]}{\text{[HA]}}\right )\\\\& = & 7.54 +\log \left(\dfrac{490}{410}\right )\\\\& = & 7.54 + \log1.195 \\& = & 7.54 +0.0774\\& = & \mathbf{7.62}\\\end{array}\\\text{The new pH is $\large \boxed{\textbf{7.62}}$}

6 0
4 years ago
The boiling points of some of the unknown will be difficult to measure using the procedure described. identify the liquids that
Tema [17]

Answer:

Methyl Alcohol.

Acetate

Heptane

Dioxane

Explanation:

The boiling point of liquids are measure by observing the gas pressure or vapors temperature. There are few liquids whose boiling point is difficult to measure. The gas pressure differs for every liquid. It is important to observe the vapor pressure also to identify the boiling point. The most difficult boiling point identification is for Methyl alcohol as it has ability to absorb different level of pressure.

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Which description is an example of gravitational potential energy transforming into kinetic energy?
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The compound responsible for the characteristic smell of garlic is allicin, The mass of 1.00 mol of allicin, rounded to the near
never [62]

Answer:

The mass of 1.00 mol of allicin, rounded to the nearest integer, is 162 g

Explanation:

Allicin is a compound that derivates from the alliin which is produced by the catalyzis of an enzime.

The molecular formula is: C₆H₁₀OS₂.

Let's determine the molar mass which is the mass that corresponds to 1 mol

Molar mass C . 6 + Molar mass H . 10 + Molar mass O + Molar mass S . 2 =

12 g/mol . 6 + 1 g/mol . 10 + 16 g/mol + 32.06 g/mol . 2 =  162.1 g/mol

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3 years ago
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