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Genrish500 [490]
3 years ago
10

I think I know this one but I don’t at the same time

Physics
1 answer:
galben [10]3 years ago
8 0

Answer: B.) 6

Explanation:

To answer this problem you get the number of students who attended Wednesday (18) and the number of students who attended Tuesday (12) and subtract 18 - 12 = 6

Answer = B.) 6

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Two technicians are discussing fuse testing. Technician A says that a test light should light on both test points of the fuse if
Murljashka [212]

Answer:

C. Both technicians A and B

Explanation:

Both technicians are absolutely correct because a functional test light is meant to light on both test point if the fuse is working fine which implies that, if the test light doesn't light on both sides then there must be a fault with the fuse. So, both technicians A and B are very correct.

4 0
3 years ago
What is the kinetic energy of a 1500kg car with a velocity of 72.0km/h?
Sergeu [11.5K]
KE=0.5 * mass* speed^2

Convert 72 km/h to m/s by dividing it by 3.6

72/3.6= 0.277778m/s

KE=0.5*1500*0.277778
= 208.3335J
= 208J
3 0
3 years ago
What is a star's main fuel during its lifetime? A. hydrogen B. carbon C. helium D. oxygen
Flura [38]
<span>The star's main fuel during its lifetime is hydrogen. It is said that a star is composed of 97% hydrogen and 3% helium. Once the hydrogen of a star is gone, the star becomes old because it burns hydrogen during its lifetime.</span>
6 0
3 years ago
Anyone know this question?
rodikova [14]

Answer:

The answer is Gravitational pull

7 0
2 years ago
The rotational kinetic energy term is often called the kinetic energy in the center of mass, while the translational kinetic ene
Nataliya [291]

Question in proper order

The rotational kinetic energy term is often called the <em>kinetic energy </em><em>in</em> the center of mass, while the translational kinetic energy term is called the <em>kinetic energy </em><em>of</em> the center of mass.

You found that the total kinetic energy is the sum of the kinetic energy in the center of mass plus the kinetic energy of the center of mass. A similar decomposition exists for angular and linear momentum. There are also related decompositions that work for systems of masses, not just rigid bodies like a dumbbell.  

It is important to understand the applicability of the formula  

Ktot=Kr+Kt

Which of the following conditions are necessary for the formula to be valid?

a. The velocity vector v  must be perpendicular to the axis of rotation

b.The velocity vector v  must be perpendicular or parallel to the axis of rotation

c. The moment of inertial must be taken about an axis through the center of mass

Answer:

Option c

Explanation:

K_{total} = K_{rotational}+K_{translational}

The first two conditions are untrue, this is because, you can have rotation in any direction and translation in any direction of any collection of masses. Rotational and translational velocities of masses do not depend on each other

The last statement is true because by definition, the moment of inertia, which is a measure of reluctance, is usually taken about a reference point which is the center of mass

4 0
3 years ago
Read 2 more answers
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