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Genrish500 [490]
3 years ago
10

I think I know this one but I don’t at the same time

Physics
1 answer:
galben [10]3 years ago
8 0

Answer: B.) 6

Explanation:

To answer this problem you get the number of students who attended Wednesday (18) and the number of students who attended Tuesday (12) and subtract 18 - 12 = 6

Answer = B.) 6

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Which form of energy body will possess when it is kept on the top of Hill
Oduvanchick [21]

Potential energy would be the answer


:)

3 0
3 years ago
Read 2 more answers
What is the energy of a photon with a frequency of 1.7 × 1017 Hz? Planck’s constant is 6.63 × 10–34 J•s.
Karo-lina-s [1.5K]
The energy carried by a single photon is given by
E=hf
where h is the Planck's constant and f is the frequency of the photon.

The photon of our exercise has a frequency of f=1.7 \cdot 10^{17} Hz, therefore its energy is
E=hf=(6.63 \cdot 10^{-34}Js)(1.7 \cdot 10^{17} Hz)=1.1 \cdot 10^{-16} J
3 0
3 years ago
Read 2 more answers
Which of the following phenomena are due to the electric interaction? (Select all that apply.) surface tension in water friction
Eddi Din [679]

Answer:

Surface tension in water

Friction between tires and pavement

Dissolution of salt in water

Explanation:

Surface tension in water: It is due to the electrostatic force of attraction (cohesive force) between water molecules.

Friction between tires and pavement: It is due to the attractive force between tires and pavement.

Dissolution of salt in water: The ions of Na ^ + and Cl ^ - separate due to the strong attraction of water molecules.

5 0
3 years ago
Two identical parallel plate capacitors A and B connected to a battery of V volts w/ the switch S closed. The switch is now open
Basile [38]
The electrostatic energy stored in a capacitor with capacitance C_0, with a voltage difference V applied to it, and without dielectric, is given by
U_0 =  \frac{1}{2} C_0 V^2
Now let's assume we fill the space between the two plates of the capacitor with a dielectric with constant k. The new capacitance of the capacitor is
C_k = k C_0
So, the energy stored now is
U_k =  \frac{1}{2}C_k V^2= \frac{1}{2}kC_0 V^2

Therefore, the ratio between the energies stored in the capacitor before and after the introduction of the dielectric is
\frac{U_k}{U_0}= \frac{ \frac{1}{2}kC_0 V^2 }{ \frac{1}{2} C_0 V^2}=  k
5 0
3 years ago
A uniform disk has a mass of 3.7 kg and a radius of 0.40 m. The disk is mounted on frictionless bearings and is used as a turnta
nevsk [136]

Answer:

1.25 kgm²/sec

Explanation:

Disk inertia, Jd =

Jd = 1/2 * 3.7 * 0.40² = 0.2960 kgm²

Disk angular speed =

ωd = 0.1047 * 30 = 3.1416 rad/sec

Hollow cylinder inertia =

Jc = 3.7 * 0.40² = 0.592 kgm²

Initial Kinetic Energy of the disk

Ekd = 1/2 * Jd * ωd²

Ekd = 0.148 * 9.87

Ekd = 1.4607 joule

Ekd = (Jc + 1/2*Jd) * ω²

Final angular speed =

ω² = Ekd/(Jc+1/2*Jd)

ω² = 1.4607/(0.592+0.148)

ω² = 1.4607/0.74

ω² = 1.974

ω = √1.974

ω = 1.405 rad/sec

Final angular momentum =

L = (Jd+Jc) * ω

L = 0.888 * 1.405

L = 1.25 kgm²/sec

4 0
4 years ago
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