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Genrish500 [490]
3 years ago
10

I think I know this one but I don’t at the same time

Physics
1 answer:
galben [10]3 years ago
8 0

Answer: B.) 6

Explanation:

To answer this problem you get the number of students who attended Wednesday (18) and the number of students who attended Tuesday (12) and subtract 18 - 12 = 6

Answer = B.) 6

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What is happening if energy input remains constant and voltage remains the same in a circuit, but the current decreases?
DENIUS [597]
<span>Ohm's law deals with the relation between voltage and current in an ideal conductor. It states that: Potential difference across a conductor is proportional to the current that pass through it. It is expressed as V=IR. The correct answer from the choices listed above is option A. The resistance has increased. </span>
8 0
3 years ago
Read 2 more answers
Gold is used to make a super thin layer on the visors of astronauts' helmets because of which property in particular?
denis-greek [22]

Answer: C. good reflector of heat

Explanation:

In space, sunlight transfers heat by radiation to objects and bodies and this includes satellites and astronauts. In addition, although the peak of the sun's emission is in the visible region of the electromagnetic spectrum, a part is also emitted in infrared (transferring thermal energy or heat) and ultraviolet (especially in the upper part of the Earth's atmosphere).

That is why in space missions, objects and many satellites are covered by thin layers or sheets that reflect this thermal energy and thus avoid damaging the equipment due to high temperatures.

In this sense, among the reflective materials used are aluminum, silver, copper and gold; the latter being the most used because it does not corrode or oxidize (unlike silver and copper) and is more malleable than aluminum.

On the other hand, <u>astronauts are also vulnerable to the effects of infrared radiation, especially their eyes</u>, since the human eye has no receptors in the infrared spectrum. <u>That is why the astronaut's helmet visor is covered with a thin layer of gold to avoid the dangerous effects of solar radiation.</u>

4 0
4 years ago
Calculate the change internal energy (δe) for a system that is giving off 45.0 kj of heat and is performing 855 j of work on th
adelina 88 [10]
The change in internal energy of a system is given by (second law of thermodynamics)
\Delta U = Q + W
where Q is the heat absorbed by the system and W is the work done on the system.

In order to correctly evaluate the internal energy change, we must be careful with the signs of Q and W:
Q positive -> Q absorbed by the system
Q negative -> Q released by the system
W positive -> W done on the system by the surroundings
W negative -> W done by the system on the surroundings

In our problem, the heat released by the system is Q=-45 kJ=-45000 J (with negative sign since it is released by the system), and the work done is W=-855 J still with negative sign because it is performed by the system on the surrounding, so the change in internal energy is
\Delta U = Q +W=-45000 J - 855 J=-45855 J
3 0
3 years ago
A simple pendulum, 2.0 m in length, is released with a push when the support string is at an angle of 25° from the vertical. If
hammer [34]

Answer: 2.3m/s

Explanation:

mass-energy balance: ke(f) + pe(f) = ke(o) + pe(o)

since we are looking for the point at the bottom of the pendulum, thats the reference point, the lowest in the system. pe(f) is 0, since h

ke(f)=0.5m x v(f)^2

pe(f)=0

ke(o)=0.5m x v(o)^2

pe(o)-mxgxh

find h by: drawing a triangle with the pendulum at the vertical, then displaced by 25 degrees , The difference in height is h, because cos(25)=(adj)/(hyp)=(2-h)/2. I found h=0.187m

In the m-e balance, cancel the masses in all the terms.

.5xv(f)^2 =0.5v(o)^2 +gxh

Given v(o) = 1.2 m/s and g = 9.8 then v(f) = 2.2595 m/s

Therefore V(0) = 2.3 m/s

8 0
4 years ago
I really need help with this
katen-ka-za [31]

<u>C</u> is the correct answer, because energy cannot be created neither destroy. The energy is changing from chemical to from electric to light, and from light to heat.  

8 0
3 years ago
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