The radius of its orbit, measured from Earth's center, will be 1.44 × 10⁷ mm.
<h3>What is Newton's law of gravitation?</h3>
Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
Given data in problem is;
The mass of Earth is, 
Gravitational constant, G =6.674 × 10⁻¹¹ N m₂/kg²
The gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
The centripetal force due to rotation of the satellite;
The centripetal and the gravitational force are equal;
![\rm F_g = F_c \\\\ \frac{Gm_sm_e}{r^2} = \frac{m_s v^2}{r} \\\\ r = G \frac{m_E }{v^2 } \\\\ r = G \frac{m_E }{(r \omega )^2 } \\\\ r = \sqrt[3]{\frac{Gm_E}{\omega^2}} \\\\ r = \sqrt[3]{\frac{6.67 \times 10^{-11}(5.98 \times 10^{24})}{(3.63 \times 10^{-4})^2}} \\\\ r = 1.44 \times 10^7 \ mm](https://tex.z-dn.net/?f=%5Crm%20F_g%20%3D%20F_c%20%20%5C%5C%5C%5C%20%20%5Cfrac%7BGm_sm_e%7D%7Br%5E2%7D%20%3D%20%20%5Cfrac%7Bm_s%20v%5E2%7D%7Br%7D%20%5C%5C%5C%5C%20r%20%3D%20G%20%5Cfrac%7Bm_E%20%7D%7Bv%5E2%20%7D%20%5C%5C%5C%5C%20r%20%3D%20G%20%5Cfrac%7Bm_E%20%7D%7B%28r%20%5Comega%20%29%5E2%20%7D%20%5C%5C%5C%5C%20r%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7BGm_E%7D%7B%5Comega%5E2%7D%7D%20%5C%5C%5C%5C%20r%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B6.67%20%5Ctimes%2010%5E%7B-11%7D%285.98%20%5Ctimes%2010%5E%7B24%7D%29%7D%7B%283.63%20%5Ctimes%2010%5E%7B-4%7D%29%5E2%7D%7D%20%5C%5C%5C%5C%20r%20%3D%201.44%20%5Ctimes%2010%5E7%20%20%20%5C%20mm)
Hence, the radius of its orbit measured from Earth's center will be 1.44 × 10⁷ mm.
To learn more about Newton's law of gravitation, refer to the link.
brainly.com/question/9699135.
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Answer:
1.58 W
Explanation:
Since the sound spreads uniformly in all directions, it must be in a form of a circle with radius of 12 m. So the area of the circle is
From the intensity of the sound we can calculate the power at 12 m
When air is blown into the open pipe,
L = 
where nis any integral number 1,2,3,4 etc. and λ is the wavelength of the oscillation
⇒λ=
Note here that n=1 is for fundamental, n=2 is first harmonic and so on..
⇒ third harmonic will be n=4
Given L=6m, n=4, solving for λ we get:
λ=
=3m
Relationship of frequency(f), velocity of sound (c) and wavelength(λ) is:
c=f.λ Or f= 
⇒f=
≈115 Hz
The speed of electromagnetic waves in a vacuum is the same as the speed of light. It can be measured by finding the frequency and wavelength of two different waves, and then by that correlation, the speed of the waveform.
Hope this helps you (:
