Molar mass
NH3 = 17 g/mol
N2 = 28 g/mol
4 NH3 + 6 NO = 5 N2 + 6 H2O
4 x 17 g NH3 ------------ 5 x 28 g N2
?? g NH3 --------------- 300 g N2
300 x 4 x 17 / 5 x 28 =
20400 / 140 => 145.71 g of NH3
The empirical formula : C₁₂H₄F₇
The molecular formula : C₂₄H₈F₁₄
<h3>Further explanation</h3>
mol C (MW=12 g/mol)
![\tt \dfrac{18.24}{12}=1.52](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B18.24%7D%7B12%7D%3D1.52)
mol H(MW=1 g/mol) :
![\tt \dfrac{0.51}{1}=0.51](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B0.51%7D%7B1%7D%3D0.51)
mol F(MW=19 g/mol)
![\tt \dfrac{16.91}{19}=0.89](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B16.91%7D%7B19%7D%3D0.89)
mol ratio of C : H : O =1.52 : 0.51 : 0.89=3 : 1 : 1.75=12 : 4 : 7
Empirical formula : C₁₂H₄F₇
(Empirical formula)n=molecular formula
( C₁₂H₄F₇)n=562 g/mol
(12.12+4.1+7.19)n=562
(281)n=562⇒ n =2
Molecular formula : C₂₄H₈F₁₄
It evaporates as the CO2 transitions from solid to gas form.