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Dmitry_Shevchenko [17]
2 years ago
13

What is the process of solvation of ionic solids in water?

Chemistry
1 answer:
Brums [2.3K]2 years ago
8 0
The solvation is the process that causes the dissolution of ionic solids, because the energy released compensates for the energy required to break the Crystal network. <span>Occurs only with polar solvents. </span><span>The solvation in which the solvent is water is called hydration.

hope this helps!</span>
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Alkaline earth metals
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4 0
2 years ago
Someone please help me before 1:00
DiKsa [7]

independent variable: how much bread there is

dependant variable: temperature, location, time, size.

hypothesis, the one with the bread will be way more moist than the one without.

control group: no bread at all.

experimental group: brownies with bread

constants: same tupperware, placement, time, size.

7 0
3 years ago
A crane lifts a 5,800-N block from the ground to 20 m above the ground in 80 seconds. How much Power
earnstyle [38]

Answer:

1450 W

Explanation:

<u>5800n x 20m</u>        =1450w

      80s

3 0
3 years ago
The burning of propane gas can be represented as a balanced chemical reaction as follows: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g) Calcula
Snezhnost [94]

Answer: 20L of H2O

Explanation:

C3H8 + 5O2 → 3CO2 + 4H2O

Recall 1mole of a gas contains 22.4L at stp

5moles of O2 contains = 5 x 22.4 = 112L

4moles of H2O contains = 4 x 22.4 = 89.6L

From the equation,

112L of O2 produced 89.6L H2O

There for 25L of O2 will produce XL of H2O i.e

XL of H2O = (25 x 89.6)/112 = 20L

6 0
3 years ago
Sodium azide, NaN3, the explosive compound found in automobile air bags, decomposes according to the following equation: 2NaN3(s
shutvik [7]

Answer:

1.9 × 10² g NaN₃

1.5 g/L

Explanation:

Step 1: Write the balanced decomposition equation

2 NaN₃(s) ⇒ 2 Na(s) + 3 N₂(g)

Step 2: Calculate the moles of N₂ formed

N₂ occupies a 80.0 L bag at 1.3 atm and 27 °C (300 K). We will calculate the moles of N₂ using the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 1.3 atm × 80.0 L / (0.0821 atm.L/mol.K) × 300 K = 4.2 mol

We can also calculate the mass of nitrogen using the molar mass (M) 28.01 g/mol.

4.2 mol × 28.01 g/mol = 1.2 × 10² g

Step 3: Calculate the mass of NaN₃ needed to form 1.2 × 10² g of N₂

The mass ratio of NaN₃ to N₂ is 130.02:84.03.

1.2 × 10² g N₂ × 130.02 g NaN₃/84.03 g N₂ = 1.9 × 10² g NaN₃

Step 4: Calculate the density of N₂

We will use the following expression.

ρ = P × M / R × T

ρ = 1.3 atm × 28.01 g/mol / (0.0821 atm.L/mol.K) × 300 K = 1.5 g/L

5 0
2 years ago
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