<span>The correct answer is that an ionic bond forms between charged particles. To form this bond, the particles transfer valence electrons (those in the outermost orbit). Specifically, in ionic bonding, the metal atom loses its electrons (thus becoming positive) and the nonmetal atom gains electrons (thus becoming negative).</span>
Answer:
+1
Explanation:
For the equation to be balanced, the total mass number and the total atomic number on both side of the equation but be equal.
This is illustrated:
For the mass number:
Left side: 22
Right side: 22 + 0 = 22
For the atomic number:
Left side: 11
Right side: 10 + x
11 = 10 + x
Collect like terms
x = 11 - 10
x = 1
See attachment for further explanation.
t1/2 = ln 2 / λ = 0.693 / λ
Where t1/2 is the half life of the element and λ is decay constant.
32 = 0.693 / λ
λ = 0.693 / 32 (1)
Nt = Nο eΛ(-λt) (2)
Where Nt is atoms at t time, λ is decay constant and t is the time taken.
t = 1.9 hours = 1.9 x 60 min
From (1) and (2),
Nt = Nο e⁻Λ(0.693/32)*1.9*60
Nt = 0.085Nο
Percentage = (Nt/Nο) x 100%
= (0.085Nο/Nο) x 100%
= 8.5%
Hence, Percentage of remaining atoms with the original sample is 8.5%
Answer:
1.99 atm
Explanation:
Step 1:
Data obtained from the question. This include the following:
Initial pressure (P1) = 0.520 atm
Initial temperature (T1) = 26.2°C
Initial volume (V1) = 15.4L
Final temperature (T2) = constant = 26.2°C
Final volume (V2) = 4.02L
Final pressure (P2) =..?
Step 2:
Determination of the new pressure of the gas.
Since the temperature of the gas is constant, it means the gas is obeying Boyle's law. Thus, the new pressure of the gas can be obtained by applying the Boyle's law equation as shown below:
P1V1 = P2V2
0.520 x 15.4 = P2 x 4.02
Divide both side by 4.02
P2 = (0.520 x 15.4) / 4.02
P2 = 1.99 atm
Therefore, the new pressure of the gas is 1.99 atm
