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rosijanka [135]
3 years ago
5

Which situation would create a field like the one shown here? A. an interaction between two magnetic south poles B. an interacti

on between two magnetic north poles C. an interaction between a magnetic south pole and a north pole D. an interaction between a magnetic south pole and an aluminum bar E. an interaction between a magnetic north pole and a zinc bar
Physics
2 answers:
alexgriva [62]3 years ago
4 0

Answer:

you have no picture

Explanation:

if it shows the arrows going towards eachother it is north and south. if it is not it will be either north and north or south and south

andriy [413]3 years ago
3 0

Answer:

C. an interaction between a magnetic south pole and a north pole

Explanation:

  • According to the situation the magnetic properties of the fields of the south and the north by the nature of the electrically charged electromagnets. That exerts a force and likewise, the earth also has two magnetic poles that have positive and negative properties and both oppose the each other properties.
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Two objects with a mass of 10,000-kg each and a distance of 1 meter between them.
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Answer:

d) What is the force if we doubled both the masses AND we doubled the distance

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what is the acceleration of an object that moves at a constant velocity of 2.0 meters per second for 5 seconds?
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An automobile with a standard differential turns sharply to the left. The left driving wheel turns on a 20-m radius. Distance be
Inessa05 [86]

Explanation:

The given data is as follows.

    Inner wheel Radius = 20 m,

   Distance between left and right wheel = 1.5m,

Let us assume speed of drive shaft is N rpm.

Formula to calculate angular velocity is as follows.

    Angular velocity of automobile = w = \frac{V}{R}

where,   V = linear velocity of automobile m/min,

              R = turning radius from automobile center in meter

In the given case, angular velocity remains same for inner and outer wheel but there is change in linear velocity of inner wheel and outer wheel.

Now, we assume that

         u = linear velocity of inner wheel

and,   u' = linear velocity of outer wheel.

Formula for angular velocity of inner wheel w = ,

Formula for angular velocity of outer wheel w =

Now, for inner wheels

                   w =

                      = \frac{u}{(R - d)}

                  u = V \times \frac{(R - d)}{R}

                    = V \times (1 - \frac{d}{R})

If radius of wheel is r it will cover  distance in one min.

Since, velocity of wheel is u it will cover distance u in unit time(min)

Thus,             u = 2\pi rn = V \times (1 - \frac{d}{R})

Now, rotation per minute of inner wheel is calculated as follows.

         n = \frac{V}{2 \pi r \times (1 - \frac{d}{R})}

            = \frac{V}{2 \pi r \times (1 - \frac{0.75}{20})} (since 2d = 1.5m given, d = 0.75m),

             = \frac{V}{r} \times 0.1532

So, rotation per minute of outer wheel; n' =  

                   = \frac{V}{2 \pi r \times (1 + \frac{0.75}{20})}

                   = \frac{V}{r} \times 0.1651

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