How many moles of butane (C4H10) must be burned in an excess of O2 to produce
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60.7 ml is the volume of a sample of CO2 at STP that has a volume of 75.0mL at 30.0°C and 91kPa.
Explanation:
Data given:
V1 = 75 ml
T1 = 30 Degrees or 273.15 + 30 = 303.15 K
P1 = 91 KPa
V2 =?
P2 = 1 atm or 101.3 KPa
T2 = 273.15 K
At STP the pressure is 1 atm and the temperature is 273.15 K
applying Gas Law:
=
putting the values in the equation of Gas Law:
V2 =
V2 =
V2 = 60.7 ml
at STP the volume of carbon dioxide gas is 60.7 ml.