Answer:
a mixture that is the original
Explanation:
like tea with out sugar or coke-cola with the cherry flavoring
Answer:
It's the button with the x, and a blank box above it.
Explanation:
Check the attachments, you'll see what it looks like. It will probably look different on your calculator, but the icon should be the same or similar.
Answer:
(a) 0.699 kJ/K
(b) -0.671 kJ/K
(c) 0.028 kJ/K
Explanation:
The Refrigerant-134a flows into the evaporator as a saturated liquid-vapor mixture and flows out as a saturated vapor at a saturation pressure of 160 kPa and temperature of -15.64°C (estimated from the Saturated Refrigerant-134a Temperature Table).
(a) The entropy change of the refrigerant (ΔS
) = Q/T
Q = 180 kJ
T
= -15.64 + 273.15 = 257.51 K
ΔS
= Q/T
= 180/257.51 = 0.699 kJ/K
(b) The entropy change (ΔS
) of the cooled space (ΔS
) = -Q/T
Q = -180 kJ
T
= -5 + 273.15 = 268.15 K
ΔS
= Q/T
= -180/268.15 = -0.671 kJ/K
(c) The total entropy change for this process (ΔS
) = ΔS
+ ΔS
= 0.699 - 0.671 = 0.028 kJ/K
Answer:
The final temperature of the iron is:- 38.0 °C
Explanation:
The initial temperature = 24.7 °C
Let Final temperature = T °C
Using,
Q = m C ×ΔT
Where,
Q is the heat absorbed by the iron = 85.7 J
C gas is the specific heat of the iron = 0.45 J/g °C
m is the mass of iron = 14.3 g
ΔT is the change in temperature. ( T - 24.7 ) °C
Applying the values as:
<u>Q = m C ×ΔT </u>
85.7 J = 14.3 g × 0.45 J/g °C × ( T - 24.7 ) °C
Solving for T, we get that:-
T = 38.0 °C
<u>The final temperature of the iron is:- 38.0 °C</u>