Answer:
0.34 sec
Explanation:
Low point of spring ( length of stretched spring ) = 5.8 cm
midpoint of spring = 5.8 / 2 = 2.9 cm
Determine the oscillation period
at equilibrum condition
Kx = Mg
g= 9.8 m/s^2
x = 2.9 * 10^-2 m
k / m = 9.8 / ( 2.9 * 10^-2 ) = 337.93
note : w = 
= 
= 18.38 rad/sec
Period of oscillation = 
= 0.34 sec
Answer:270joules
Explanation:KE = 1/2mv^2
KE = 1/2(60kg)(3.0)^2 = 270 Joules
Answer:
A
Explanation:
A consensus is when you come to an agreement
Answer:
the switching circuitry is opened the soft iron armature is replaced to tasty le macha the switching circuitry is closed explain what happens when the switch circuit is a wonder you know about the characteristics of open to close this which right take the example of an electric generator for an electric motor which rotates in half rotation and change the armature and just try it ok I am sorry
Answer:
Explanation:
make observations, draw conclusions, develop a hypothesis, analyze data.
