1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
____ [38]
2 years ago
11

During World War I, the Germans had a gun called Big Bertha that was used to shell Paris. The shell had an initial speed of 1.4

km/s at an initial inclination of 65.8 ◦ to the horizontal. The acceleration of gravity is 9.8 m/s 2 . How far away did the shell hit?
Physics
1 answer:
Ksju [112]2 years ago
5 0

Answer:

The shell hit at a horizontal distance 149.41 km

Explanation:

The shell had an initial speed of 1.4 km/s

Initial speed = 1400 m/s

Inclination = 65.8° to the horizontal

First let us find the time of travel

Consider the vertical motion,

We have equation of motion, s = ut + 0.5 at²

Initial velocity, u = 1400 sin 65.8 = 1276.97 m/s

Acceleration, a = -9.81 m/s²

Displacement, s = 0 m

Substituting

                 s = ut + 0.5 at²          

                 0 = 1276.97 x t + 0.5 x  (-9.81) xt²

                  t = 260.34 s

Now let us find the horizontal displacement,

Consider the horizontal motion,

We have equation of motion, s = ut + 0.5 at²

Initial velocity, u = 1400 cos 65.8 = 573.89 m/s

Acceleration, a = 0 m/s²

Time, t = 260.34 s

Substituting

                 s = ut + 0.5 at²          

                 s = 573.89 x 260.34 + 0.5 x  0 x 260.34²

                  s = 149407.11 m = 149.41 km

The shell hit at a horizontal distance 149.41 km

You might be interested in
A mass of 2 kg traveling at 3 m/s undergoes a one-dimensional elastic collision with a group of four 1kg masses that are at rest
alukav5142 [94]
2kg + 3 kg = 5 kg as result of the conclusion
6 0
3 years ago
A swift blow with the hand can break a pine board. As the hand hits the board, the kinetic energy of the hand is transformed int
Stells [14]

Answer:

A. The hand must move with a velocity of 6.98 m/s to break the board.

B. Average force on the hand = 1025 N

Explanation:

A.To determine the speed the hand must move with to break the board, the force workdone in breaking the board is found first.

Workdone = force × distance

Minimum force required = 870 N;

Distance moved by board/Deflection in order to break = 1.4 cm = 0.014 M

Workd done = 870 N × 0.014 m = 12.18 Nm or 12.18 J

This work done = Kinetic energy of the hand

Kinetic energy = mv²/2 ; where m is mass and v is velocity

Mass of hand = 0.50 Kg, velocity = ?, K.E. = 12.18 J

v² = 2 KE/m

v = √2KE/m

v = √(2 × 12.18/0.50)

v = 6.98 m/s

Therefore, the hand must move with a velocity of 6.98 m/s to break the board.

B. Average force on the hand

This can be determined using the equation of motion, v² = u² + 2as to find acceleration, since force = mass × acceleration

From the equation of motion, a = v² - u²/2s

At rest, v = 0, u = 6.98, s = 1.2 cm = 0.012 m

a = 0² - 6.98²/ 2 × 0.012

a = -2030 m/s²

Force = 2030 m/s² × 0. 50 kg = 1015 N

Therefore, Average force on the hand = 1025 N

3 0
2 years ago
Two forces, one of 100 ponds and the other 150 pounds act on the same object, at angles of 20°and 60°, respectively, withthe pos
soldi70 [24.7K]
<h2>Resultant is 235.54 pounds at an angle 44.16° to X axis.</h2>

Explanation:

Forces are 100 pound and 150 pound and angles with x axis are 20°and 60°.

That is force 1 is 100 pound with x axis at 20°

           F₁ = 100 cos 20 i  +  100 sin 20 j

           F₁ = 93.97 i  +  34.20 j          

That is force 2 is 150 pound with x axis at 60°

           F₂ = 150 cos 60 i  +  150 sin 60 j

           F₂ = 75 i  +  129.90 j  

F₁ +  F₂ =  93.97 i  +  34.20 j + 75 i  +  129.90 j

F₁ +  F₂ =  168.97 i  +  164.10 j

\texttt{Magnitude = }\sqrt{168.97^2+164.10^2}\\\\\texttt{Magnitude = }235.54pounds\\\\\texttt{Angle = }tan^{-1}\left ( \frac{164.10}{168.97}\right )\\\\\texttt{Angle = }44.16^0

Resultant is 235.54 pounds at an angle 44.16° to X axis.

6 0
3 years ago
An object that is initially not rotating has a constant torque of 3.6 N⋅m applied to it. The object has a moment of inertia of 6
Korolek [52]

Answer:

0.6

Explanation:

Angular acceleration is equal to Net Torque divided by rotational inertia, which is the rotational equivalent to Newton’s 2nd Law.  Therefore, angular acceleration is equal to 3.6/6 which is 0.6. Hope this helped!

3 0
2 years ago
A pendulum has 576 J of potential energy at the highest point of its swing. How much kinetic energy will it have at the bottom o
Natalka [10]
Ideally, 576 J  because energy is conserved.
In the real world, a tiny tiny tiny tiny bit less than 576 J ,
because we live in a world with friction and air resistance.
3 0
3 years ago
Other questions:
  • 14. What is the standard deviation for the numbers 75,83,96,100,121 and 125?
    12·1 answer
  • Help me with Economics please and thank you the question is going to be down in a attached file while the answers on here
    7·2 answers
  • What chemical phenomenon accounts for the elasticity seen in solids?
    9·1 answer
  • Help me with this question please
    6·2 answers
  • Plzz answer this question correctly
    14·1 answer
  • Kūna veikia 3N jėga kurios petys 20 cm. Koks jos momentas?​
    9·1 answer
  • Please help will mark brainliest!
    15·2 answers
  • Is the substance below an element,compound, or mixture
    13·1 answer
  • What is meant by black hole ?​
    9·2 answers
  • How many earth years does it take mercury to go around the sun?
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!