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____ [38]
3 years ago
11

During World War I, the Germans had a gun called Big Bertha that was used to shell Paris. The shell had an initial speed of 1.4

km/s at an initial inclination of 65.8 ◦ to the horizontal. The acceleration of gravity is 9.8 m/s 2 . How far away did the shell hit?
Physics
1 answer:
Ksju [112]3 years ago
5 0

Answer:

The shell hit at a horizontal distance 149.41 km

Explanation:

The shell had an initial speed of 1.4 km/s

Initial speed = 1400 m/s

Inclination = 65.8° to the horizontal

First let us find the time of travel

Consider the vertical motion,

We have equation of motion, s = ut + 0.5 at²

Initial velocity, u = 1400 sin 65.8 = 1276.97 m/s

Acceleration, a = -9.81 m/s²

Displacement, s = 0 m

Substituting

                 s = ut + 0.5 at²          

                 0 = 1276.97 x t + 0.5 x  (-9.81) xt²

                  t = 260.34 s

Now let us find the horizontal displacement,

Consider the horizontal motion,

We have equation of motion, s = ut + 0.5 at²

Initial velocity, u = 1400 cos 65.8 = 573.89 m/s

Acceleration, a = 0 m/s²

Time, t = 260.34 s

Substituting

                 s = ut + 0.5 at²          

                 s = 573.89 x 260.34 + 0.5 x  0 x 260.34²

                  s = 149407.11 m = 149.41 km

The shell hit at a horizontal distance 149.41 km

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Which of the following statements about the Coriolis effect is correct?
labwork [276]

Answer:

Option D

The Coriolis effect works at right angles to the direction of airflow

Explanation:

At the equator, Coriolis effect is negligible, basically zero while it's strongest at the poles (to imply statement B is wrong). Moreover, Coriolis effect is affected by the speed of wind and it also affects the speed of wind since when the wind speed decreases, due to friction for example, the Coriolis effect is also reduces.

7 0
3 years ago
Two objects of equal mass collide on a horizontal frictionless surface. Before the collision, object A is at rest while object B
fenix001 [56]

Answer: 6m/s

Explanation:

Using the law of conservation of momentum, the change in momentum of the bodies before collision is equal to the change in momentum after collision.

After collision, the two objects will move at the same velocity (v).

Let mA and mB be the mass of the two objects

uA and uB be their velocities before collision.

v be their velocity after collision

Since the two objects has the same mass, mA= mB= m

Also since object A is at rest, its velocity = 0m/s

Velocity of object B = 12m/s

Mathematically,

mAuA + mBuB = (mA+mB )v

m(0) + m(12) = (m+m)v

0+12m = (2m)v

12m = 2mv

12 = 2v

v = 6m/s

Therefore the speed of the composite body (A B) after the collision is 6m/s

7 0
3 years ago
1. Two blocks travel along a level frictionless surface. Block A is initially moving to the right at 5.0 m/s, while block B is i
ad-work [718]

Answer: 2.67 m/s

Explanation:

Given

Mass of block A  is m_a=2\ kg

mass of block B is m_b=3\ kg

The initial velocity of block A u_a=5\ m/s

the initial velocity of block B is u_b=0

After collision velocity of block A is v_a=1\ m/s

Conserving momentum

m_au_a+m_bu_b=m_av_a+m_bv_b\\\\2\times 5+3\times0=2\times 1+3\times v_b\\\\v_b=\dfrac{8}{3}=2.67\ m/s

The momentum of block A after the collision is P_a=2\times 1=2\ kg.m/s

Therefore, there is no change in sign.

6 0
3 years ago
The inner and outer surfaces of a cell membrane carry a negative and positive charge, respectively. Because of these charges, a
BlackZzzverrR [31]

Answer:

E = 8.5 * 10^6 V/m

Explanation:

In general we have the following relation between the Electric Field and the Elecric Potential:

\int\limits^2_1 {\vec{E} \cdot\vec{dl}} = V_{2} -V_{1}

Due to the vector nature of the electric filed, we can only know the mean Electric field E across the membrane, and take it out from the integral, that is:

E = (ΔV)/L

Where L is the thickness of the membrane and ΔV is the potential difference.

Therefore:

E = 8.53933*10^6 V/m

rounding to the first tenth:

E = 8.5 * 10^6 V/m

3 0
3 years ago
In which situation is no work considered to be done by a force?
andre [41]
If the angle is either 0 or 180, that means that there is either negative or positive work, so A and D are not correct.
If the angle is 45, then there is still some work involved.
The only option where there is no work done by a force is B. when the angle is between the force and displacement is 90. 
8 0
3 years ago
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