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Ulleksa [173]
3 years ago
8

Which of the following includes the correct pairing of volcano and its formation? Cinder volcano; large, explosive eruptions Cin

der volcano; alternating quiet and explosive eruptions Shield volcano; large, quiet eruptions Composite volcano; large; violent eruptions
Chemistry
2 answers:
noname [10]3 years ago
6 0

Shield volcano; large, quiet eruptions

Anarel [89]3 years ago
4 0
The correct pairing of the volcano to its formation would be the composite volcano wherein it usually yields large and violent eruptions. In addition to that, composite volcanoes or also known as the stratovolcano is usually made of materials containing increasing layers of hardened lava.
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The atomic weight of copper is 63.546 amu. The two naturally occuring isotopes of copper have the following masses 63Cu, 62.9298
strojnjashka [21]

Answer:

The percent isotopic abundance of Cu-65 is 30.79 %.

The percent isotopic abundance of Cu-63 is 69.21 %.

Explanation:

we know there are two naturally occurring isotopes of carbon, Cu-63 (62.9298 amu)  and Cu-65 (64.9278 amu)

First of all we will set the fraction for both isotopes

X for the isotopes having mass 62.9298 amu

1-x for isotopes having mass 64.9278 amu

The average atomic mass of copper is 63.546 amu.

we will use the following equation,

62.9298 x + 64.9278 (1-x) = 63.546

62.9298x +  64.9278 -  64.9278x = 63.546

62.9298x - 64.9278x = 63.546  - 64.9278

-1.998 x = -1.3828

x=-1.3828 / -1.998

x= 0.6921

0.6921 × 100 = 69.21 %

69.21 % is abundance of Cu-63 because we solve the fraction x.

now we will calculate the abundance of Cu-65.

(1-x)

1-0.6921 = 0.3079

0.3079 × 100 = 30.79 %

30.79 % for Cu-65.

6 0
3 years ago
Complete the following equation: 250/96Cm ——-> ? + 4 1/0n
vfiekz [6]

Answer:

²⁵⁰₉₆Cm → ²⁴⁶₉₆Cm + 4 ¹₀n

Explanation:

The complete equation is;

²⁵⁰₉₆Cm → ²⁴⁶₉₆Cm + 4 ¹₀n

  • The above equation is an example of a nuclear reaction in which unstable atom of Cm emits neutrons to become more stable.
  • Radioactive isotopes undergo radioactivity or decay to attain stability, they do so by emitting particles such as alpha, beta particles or a neutron.
  • An atom of Cm-250 undergoes decay and emits four neutrons to form an atom of Cm-246.
3 0
3 years ago
What does the energy hill represent on an energy diagram?
Leokris [45]

B.The potential energy the reactants have stored in molecular bonds

6 0
3 years ago
Ammonia gas has a molar mass of approximately 17 grams per mole. At 290k and 1.2 atm, a sample of ammonia has a volume of 3.7 L.
dlinn [17]

We have that for the Question, it can be said that the mass of Ammonia is

Mass_a=3.162grams

From the question we are told

<em>Ammonia </em>gas has a <u>molar</u> mass of approximately 17 <u>grams </u>per mole. At 290k and 1.2 atm, a sample of <em>ammonia </em>has a volume of 3.7 L. In <em>three </em>to five sentences, explain how you can find the mass of the <em>ammonia</em>. Then, given R= 0.0821L.atm/mol.k, calculate the mass.

Generally the equation for the   is mathematically given as

PV=nRT\\\\n=\frac{PV}{RT}\\\\n=0.186 moles\\\\

Now the mass of ammonia is

Mass_a=0.186*17\\\\Mass_a=3.162grams

Hence the mass of Ammonia is

Mass_a=3.162grams

For more information on this visit

brainly.com/question/23379286

3 0
3 years ago
Read 2 more answers
Make the following conversion. 0.075 m = _____ cm 7.5 75 0.0075 0.00075
GaryK [48]
In the given question we need to convert 0.075 meter into centimeter. For this purpose we need to know the relation between meter and centimeter. Then only this problem can be solved and the correct answer reached.
Now we know that
1 meter = 100 centimeter
Then
0.075 meter = [(100/1) * 0.075] centimeter
We know that any number when divided by 1 gives the same number.
So
0.075 meter = (100 * 0.075) centimeter
                    = (100 * 75/1000) centimeter
                    = (7500/1000) centimeter
                    = (75/10) centimeter
                    = 7.5 centimeter.
So from all the given options the correct answer to the question is 7.5 centimeter.  
8 0
3 years ago
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